-2 for each O
+6 for S
In SO3, sulfur has an oxidation number of +6 and each oxygen atom has an oxidation number of -2.
The oxidation number of Na in Na2SO3 is +1, the oxidation number for S in SO3 is +4, and the oxidation number for O in SO3 is -2.
The oxidation number of the sulfur atom in SO3 is +6. Each oxygen atom is assigned an oxidation number of -2, so by balancing the charges and knowing that the overall charge of the molecule is 0, sulfur must have an oxidation number of +6.
If you mean SO3^-2 (the sulfite anion), then S has an oxidation number of 4+, since each O atom is 2-. In sulfur trioxide, SO3, the S atom has an oxidation number of 6+.
The oxidation number of zinc (Zn) is always +2. For hydrogen (H), it is +1. For sulfur (S) in the sulfite ion (SO3^2-), it is +4 and for oxygen (O), it is always -2. By adding up the oxidation numbers of each element in ZnHSO3^2-, we find that the oxidation number of sulfur is +6.
Sulfur has an oxidation state of +4 in SO3^2-. Each oxygen atom has an oxidation state of -2.
In SO3, sulfur has an oxidation number of +6 and each oxygen atom has an oxidation number of -2.
The oxidation number of Na in Na2SO3 is +1, the oxidation number for S in SO3 is +4, and the oxidation number for O in SO3 is -2.
The oxidation number of the sulfur atom in SO3 is +6. Each oxygen atom is assigned an oxidation number of -2, so by balancing the charges and knowing that the overall charge of the molecule is 0, sulfur must have an oxidation number of +6.
If you mean SO3^-2 (the sulfite anion), then S has an oxidation number of 4+, since each O atom is 2-. In sulfur trioxide, SO3, the S atom has an oxidation number of 6+.
The oxidation number of zinc (Zn) is always +2. For hydrogen (H), it is +1. For sulfur (S) in the sulfite ion (SO3^2-), it is +4 and for oxygen (O), it is always -2. By adding up the oxidation numbers of each element in ZnHSO3^2-, we find that the oxidation number of sulfur is +6.
When calculating oxidation numbers, use '-2' (oxygen) as the 'yardstick'(standard). Since SO3 has three oxygens, then the oxygen moiety is 3 x -2 = -6 Since SO3 is a neutrally charged molecule, overall oxidation is '0'. Hence S + -6 = 0 Hence S = 6 is the oxudation number for sulphur. NB Sulphur exhibits different oxidation states in different molecules. S = 0 SO2 = 4 SO3 = 6 ( as above) H2SO4) = 6 H2S2O7 (Oleum) = 6
The oxidation state of sulfur in SO3 is +6. Each oxygen atom has an oxidation state of -2, and since the overall charge of SO3 is 0, the oxidation state of sulfur must be +6 to balance out the charges.
The oxidation state for sulfur (S) in SO3 is +6. Each oxygen atom in SO3 has an oxidation state of -2, and since the overall molecule is neutral, the sum of the oxidation states must equal zero. Therefore, sulfur must have an oxidation state of +6 to balance the -6 from the three oxygen atoms.
+6, because the oxidation number of oxygen is -2x3=-6
For CaSO4 (calcium sulfate), the oxidation number of sulfur is +6. For SO4 (sulfate ion), the oxidation number of sulfur is +6. For SO2 (sulfur dioxide), the oxidation number of sulfur is +4. For SO3 (sulfur trioxide), the oxidation number of sulfur is +6.
In NH4₂SO3, the oxidation number of N is -3 (since H is +1), the oxidation number of S is +3, and the oxidation number of O is -2. The sum of the oxidation numbers in a neutral compound is always zero, so the oxidation number of H is +1.