S is +6, O is -2
In SO3, sulfur has an oxidation number of +6 and each oxygen atom has an oxidation number of -2. The sum of the oxidation numbers must equal the overall charge of the molecule, which in this case is 0.
The oxidation number of Na in Na2SO3 is +1, the oxidation number for S in SO3 is +4, and the oxidation number for O in SO3 is -2.
The oxidation state of sulfur in SO3 is +6. Each oxygen atom has an oxidation state of -2, and since the overall charge of SO3 is 0, the oxidation state of sulfur must be +6 to balance out the charges.
If you mean SO3^-2 (the sulfite anion), then S has an oxidation number of 4+, since each O atom is 2-. In sulfur trioxide, SO3, the S atom has an oxidation number of 6+.
When calculating oxidation numbers, use '-2' (oxygen) as the 'yardstick'(standard). Since SO3 has three oxygens, then the oxygen moiety is 3 x -2 = -6 Since SO3 is a neutrally charged molecule, overall oxidation is '0'. Hence S + -6 = 0 Hence S = 6 is the oxudation number for sulphur. NB Sulphur exhibits different oxidation states in different molecules. S = 0 SO2 = 4 SO3 = 6 ( as above) H2SO4) = 6 H2S2O7 (Oleum) = 6
The oxidation number is 0 in elemental form. It can have other oxidation numbers as -2, +4 and +6 in its compounds such as H2S, SO2 and SO3 respectively.-2, 0, 2, 4 and 6 oxidation states
In SO3, sulfur has an oxidation number of +6 and each oxygen atom has an oxidation number of -2. The sum of the oxidation numbers must equal the overall charge of the molecule, which in this case is 0.
The oxidation number of Na in Na2SO3 is +1, the oxidation number for S in SO3 is +4, and the oxidation number for O in SO3 is -2.
The oxidation state of sulfur in SO3 is +6. Each oxygen atom has an oxidation state of -2, and since the overall charge of SO3 is 0, the oxidation state of sulfur must be +6 to balance out the charges.
Sulfur has an oxidation state of +4 in SO3^2-. Each oxygen atom has an oxidation state of -2.
If you mean SO3^-2 (the sulfite anion), then S has an oxidation number of 4+, since each O atom is 2-. In sulfur trioxide, SO3, the S atom has an oxidation number of 6+.
When calculating oxidation numbers, use '-2' (oxygen) as the 'yardstick'(standard). Since SO3 has three oxygens, then the oxygen moiety is 3 x -2 = -6 Since SO3 is a neutrally charged molecule, overall oxidation is '0'. Hence S + -6 = 0 Hence S = 6 is the oxudation number for sulphur. NB Sulphur exhibits different oxidation states in different molecules. S = 0 SO2 = 4 SO3 = 6 ( as above) H2SO4) = 6 H2S2O7 (Oleum) = 6
In NH4₂SO3, the oxidation number of N is -3 (since H is +1), the oxidation number of S is +3, and the oxidation number of O is -2. The sum of the oxidation numbers in a neutral compound is always zero, so the oxidation number of H is +1.
The oxidation state for sulfur (S) in SO3 is +6. Each oxygen atom in SO3 has an oxidation state of -2, and since the overall molecule is neutral, the sum of the oxidation states must equal zero. Therefore, sulfur must have an oxidation state of +6 to balance the -6 from the three oxygen atoms.
SO3 is a covalent compound, not ionic. It is called sulfur trioxide.
In SO3^2-, sulfur has an oxidation state of +4 (Sulfur's typical oxidation state is +6 and each oxygen has an oxidation state of -2, so the total charge of the ion of -2 corresponds to sulfur being in a +4 oxidation state).
The oxidation number of the sulfur atom in SO3 is +6. Each oxygen atom is assigned an oxidation number of -2, so by balancing the charges and knowing that the overall charge of the molecule is 0, sulfur must have an oxidation number of +6.