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To calculate oxidation numbers. Use oxygen at '-2' as the standard. It does vary in specific cases , but '-2' is the best starting point.

In H2SO4

There are 4 x oxygen , hence 4 x -2 = -8

So the oxygen moiety is '-8'. So the hydrogen and Sulphur MUST come to '+8'.

Since hydrogen is 'H^+' in Sulphuric Acid, its oxidation no. is '+1'

So there are 2 x hydrogen , hence 2 x +1 = +2

Since sulphuric acid is a neutrally charged compound, then

+2 + S - 8 = 0

Hence S = 8 - 2 = +6 THe oxidation no. of sulphur. in sulphuric acid.

NB The oxidation no. of sulphur can vary is different compounds.

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lenpollock

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1y ago

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