To calculate oxidation numbers. Use oxygen at '-2' as the standard. It does vary in specific cases , but '-2' is the best starting point.
In H2SO4
There are 4 x oxygen , hence 4 x -2 = -8
So the oxygen moiety is '-8'. So the hydrogen and Sulphur MUST come to '+8'.
Since hydrogen is 'H^+' in Sulphuric Acid, its oxidation no. is '+1'
So there are 2 x hydrogen , hence 2 x +1 = +2
Since sulphuric acid is a neutrally charged compound, then
+2 + S - 8 = 0
Hence S = 8 - 2 = +6 THe oxidation no. of sulphur. in sulphuric acid.
NB The oxidation no. of sulphur can vary is different compounds.
The oxidation number of sulfur in H2SO4 is +6. This is because hydrogen has an oxidation number of +1 and oxygen has an oxidation number of -2, so by the rules of oxidation numbers, sulfur must have an oxidation number of +6 to balance the equation.
The oxidation number of sulfur in H2SO4 is +6. This is because each hydrogen atom has an oxidation number of +1 and each oxygen atom has an oxidation number of -2. Since the overall charge of the molecule is 0, the oxidation number of sulfur must be +6 to balance out the charges.
+1 for H +6 for S -2 for each O
The oxidation number of sulfur can vary depending on the compound it is in. In most cases, sulfur has an oxidation number of -2, as seen in hydrogen sulfide (H2S) or sulfur dioxide (SO2). However, in some compounds such as sulfuric acid (H2SO4), sulfur can have an oxidation number of +6.
The oxidation number of sulfur in H2SO4 is +6. This is because hydrogen is typically assigned an oxidation number of +1 and oxygen -2, leading to the equation 2(1) + x + 4(-2) = 0. Solving for x gives x = +6 for sulfur.
The oxidation number of sulfur in H2SO4 is +6. This is because hydrogen has an oxidation number of +1 and oxygen has an oxidation number of -2, so by the rules of oxidation numbers, sulfur must have an oxidation number of +6 to balance the equation.
The oxidation number of sulfur in H2SO4 is +6. This is because each hydrogen atom has an oxidation number of +1 and each oxygen atom has an oxidation number of -2. Since the overall charge of the molecule is 0, the oxidation number of sulfur must be +6 to balance out the charges.
+1 for H +6 for S -2 for each O
The oxidation number of sulfur can vary depending on the compound it is in. In most cases, sulfur has an oxidation number of -2, as seen in hydrogen sulfide (H2S) or sulfur dioxide (SO2). However, in some compounds such as sulfuric acid (H2SO4), sulfur can have an oxidation number of +6.
The oxidation number of sulfur in H2SO4 is +6. This is because hydrogen is typically assigned an oxidation number of +1 and oxygen -2, leading to the equation 2(1) + x + 4(-2) = 0. Solving for x gives x = +6 for sulfur.
The oxidation number of hydrogen is +1, the oxidation number of sulfur is +6, and the oxidation number of oxygen is -2. In H2SO4, there are 2 hydrogen atoms (totaling +2), 1 sulfur atom (+6), and 4 oxygen atoms (totaling -8). The sum of the oxidation numbers should equal the charge of the compound, which is 0, so the oxidation number of sulfur in H2SO4 is +6.
The oxidation number of hydrogen (H) in H2SO4 is +1.
The oxidation number of an atom in a compound depends on what is attached to it.The following are examples of oxidation numbers (ON #)for sulfur :S8 ON # 0H2S ON # -2SO2 ON # +4SO3 ON # +6H2SO4 ON# +6
In H2SO4, the oxidation number of H is +1, the oxidation number of S is +6, and the oxidation number of O is -2. These numbers are determined based on the rules of assigning oxidation numbers in compounds.
H2SO4 is a compound and as such does not have an oxidation number. The individual atoms in this compound have oxidation number +1 for each hydrogen atom, +6 for sulfur, and -2 for each oxygen atom.
The oxidation number of sulfur in H2SO4 is +6. This is determined by balancing the overall charge of the compound, which is 0, and taking into account the known oxidation numbers for hydrogen (+1) and oxygen (-2).
The oxidation number of sulfur in sulfuric acid (H2SO4) is +6. This is because oxygen typically has an oxidation number of -2, and there are four oxygen atoms in sulfuric acid. Each hydrogen atom has an oxidation number of +1. Using this information, we can calculate that the oxidation number of sulfur must be +6 in order for the overall charge of the molecule to be neutral.