1
Cos(360 - X) = Trig. Identity Cos(360)Cos(x) + Sin(360)Sin(x) => 1CosX + 0Sinx => CosX + o => CosX
The cos of 2pi is 360 degrees which is 1.
Cos 295 fall s in the 4th quadrant where cosine is positive cos 295 = cos (360-295) = cos 65 = 0.4226
You cannot prove it because it is not true! cos(0) = 1 cos(2*pi) = 1 cos(4*pi) = 1 ... cos(2*k*pi) = 1 for all integers k or, if you still work in degrees, cos(0) = 1 cos(360) = 1 cos(720) = 1 ... cos(k*360) = 1 for all integers k
510 ~ (510-360) ~ 150 Cos 510 = Cos 150 = - Cos 30 = - ( radical 3 ) / 2
Cos of 850 degrees?850 deg = 130 + 360*2 = 130 degBy the graph of the cosine: cos(130) = -cos(50)and cos(50) is not a fraction of a root.cos(50) = 0.6427876...Therefore, cos(850) = -0.6427876...
It is 45 + 360*k deg or 135 + 360*k degrees where k is an integer.
351
65536
no there is not a gm mode sorry
20cm=200mm
31 x 1