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Cos(360 - X) = Trig. Identity Cos(360)Cos(x) + Sin(360)Sin(x) => 1CosX + 0Sinx => CosX + o => CosX
The cos of 2pi is 360 degrees which is 1.
Cos 295 fall s in the 4th quadrant where cosine is positive cos 295 = cos (360-295) = cos 65 = 0.4226
You cannot prove it because it is not true! cos(0) = 1 cos(2*pi) = 1 cos(4*pi) = 1 ... cos(2*k*pi) = 1 for all integers k or, if you still work in degrees, cos(0) = 1 cos(360) = 1 cos(720) = 1 ... cos(k*360) = 1 for all integers k
The expression ( y \cos(\theta) ) will have its maximum value when ( \cos(\theta) ) reaches its maximum, which is 1. Since ( \theta ) is constant at 720 degrees, we can calculate ( \cos(720^\circ) ). The angle 720 degrees is equivalent to 0 degrees (since ( 720^\circ - 360^\circ = 360^\circ ), and ( 360^\circ - 360^\circ = 0^\circ )), thus ( \cos(720^\circ) = 1 ). Therefore, the maximum value of ( y \cos(θ) ) is simply ( y ) when ( \theta = 720 ) degrees.
510 ~ (510-360) ~ 150 Cos 510 = Cos 150 = - Cos 30 = - ( radical 3 ) / 2
Cos of 850 degrees?850 deg = 130 + 360*2 = 130 degBy the graph of the cosine: cos(130) = -cos(50)and cos(50) is not a fraction of a root.cos(50) = 0.6427876...Therefore, cos(850) = -0.6427876...
It is 45 + 360*k deg or 135 + 360*k degrees where k is an integer.
The cosine of 450 degrees can be found by first reducing it to an equivalent angle within the standard range of 0 to 360 degrees. Since 450 degrees is equal to 450 - 360 = 90 degrees, we find that cos(450 degrees) = cos(90 degrees). Therefore, cos(450 degrees) is equal to 0.
351
65536
no there is not a gm mode sorry