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initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
Unfortunately, the question is so vague it can't be answered specifically. But I will use my intuition and say that you are a high-school student studying algebra-based physics and are now up to the chapter or unit on rectilinear motion. If so, read on. If not, well, then perhaps you could use the discussion page to add more info (and maybe rephrase the question). The general formula for straight-line motion is a quadratic equation. Displacement (or distance) is expressed as a function of time. In other words, dispacement is the dependent variable and time is the independent variable. But displacement is also dependent upon the values of initial displacement, initial velocity, and acceleration, which are all coefficients of the general displacement formula. Here is the formula: d = d0 + v0t + (1/2)at2, where d is the displacement, d0 is the initial displacement (in other words, the displacement at t = 0), v0 is the initial velocity (velocity at t = 0), and a is the acceleration. So, using the formula, you can solve for distance traveled (displacement) if you know the values of all those parameters to the right of the equal sign. But what if you don't know the value of t? Well, in that case, you had better know the values of all the other parameters, including the d to the left of the equal sign. If you know the initial distance, the total distance traveled, the initial velocity, and the acceleration, you can solve for t. Usually, we set up our frame of reference so that d0 = 0. Frequently, v0 = 0, also. (In other words, the object has no initial displacement and no initial velocity.) If you know the distance traveled, d, and the acceleration, a, then you can solve for t using the simplified formula d = (1/2)at2. Solving for t, you get t = SQRT(2d/a).Since you now know t and d, you can calculate the object's average velocity using the formula, va = d/t. Since the object started at rest (it had zero initial velocity), its final velocity, vf, is 2va. You might be able to use the equation of motion v2 = u2 + 2ad, where v is the final velocity, u is the initial velocity, a is the acceleration & d is the distance covered. Quite often the initial velocity is zero, so the equation simply becomes v2 = 2ad. So the final velocity v =SQRT(2ad).
Impact velocity of projectile is simply its velocity at the moment of impact in reference to body it hits. For example, if a gun bullet at velocity of 800 m/s hits a car heading towards it at 20 m/s, the impact velocity would be 820 m/s.
v<sub>f</sub><sup>2</sup> - v<sub>i</sub><sup>2</sup> = 2a (x<sub>f</sub> - x<sub>i</sub)
Time of day.
Time of day.
The distance relay trips when a fault occurs at a distant or a remote place in the electric transmission line. There is a mechanism based on the impedance calculation of the distance of the transmission line after which it is accurately known where the fault has taken place. Thus the distance protective relay can trip the circuit & prevent the fault to be carried further and also can indicate the location of the fault.
Is there and Doctorial course for distance students?
That is going to vary based on what kind of "300" you are using, what the type and weight of the bullet is, what your initial velocity is, and at what distance you are sighted in for your far zero.
Displacement is a value predicated on the shortest distance between an initial and final position. If a "body" moves a certain distance and returns to its original origin it has not technically traveled any distance based on this definition. The displacement will therefore be zero
performs an action on the table on which it is based
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splitt-mopp
Magellan's circumnavigation and exploration.
They are based on initial dilation and subsequent dilation.
The relative speed is 10 mph; based on this, use the formula distance = speed x time. Solving for time: time = distance / speed. If distances are in miles, and speeds in mph, the time will obviously be in hours.