CuSO4(aq) + 2KOH(aq) --> Cu(OH)2(s) + K2SO4(aq)
K2C2O4 + CuSO4 --> K2SO4 + CuC2O4 is the most probable reaction.
1. CuSO4 + KOH → Cu(OH)2 + K2SO4
Cu+2 + SO4-2 + K+1 + OH-1 → Cu(OH)2 + K+1 + SO4-2
Cu+2 + OH-1 → Cu(OH)2
The chemical reaction is:
2 (K+ + I-)(aq) + (2 Cu+ + [SO4]2-)(aq)-------------(2 K+ + [SO4]2-)(aq) + 2 CuI(s)
K2[cu(c204)]
Combine aqueous solutions of copper(II) chloride and potassium chromate to get a precipitate of copper(II) chromate.
MnCrO4 is manganese(II) chromate
There is no reaction at all.
when these two are added, it forms double displacement. In result, copper (ii) hydroxide and potassium 2 sulfate is formed. pale blue solid is the product.
The iron will displace the copper as it is more reactive. here's the equation: iron + copper sulphate = iron sulphate +copper
Combine aqueous solutions of copper(II) chloride and potassium chromate to get a precipitate of copper(II) chromate.
Assuming you mean a reaction between potassium (K) and copper(II) sulfate, your products would be potassium sulfate and copper in a single replacement reaction. Here's the equation:2K + CuSO4 --> K2SO4 + Cu
This equation is CuSO4.5 H2O -> CuSO4 + 5 H2O.
The balanced equation for copper(II) oxide and potassium chloride is CuO + 2KCl → CuCl2 + K2O When copper(II) oxide reacts with potassium chloride then it forms copper(II) chloride and potassium oxide.
MnCrO4 is manganese(II) chromate
The chemical formula (not equation) of copper(II) sulfate is CuSO4.
The chemical equation is:Zn + CuSO4 = ZnSO4 + Cu
Fe + CuSO4 = FeSO4 + Cu
2CuS + NaCO2
There is no reaction at all.
Your question is rather broad, but here are a few. Potassium chromate yellow Aluminum chloride light yellow Ferric nitrate light violet Ferric Chloride mustard Ferrous chloride/sulfate green Copper (II) sulfate blue Cupric chloride green Nickel chloride (hydrate) green Potassium dichromate orange Potassium permanganate purple Bromine water dark red Iodine water brown
when these two are added, it forms double displacement. In result, copper (ii) hydroxide and potassium 2 sulfate is formed. pale blue solid is the product.