The ionization potential for unionized helium is 24.6 eV, the potential for singly ionized Helium is 54.4 eV. Helium has only two electrons, so there is no way to ionize the doubly ionized helium. (So there also is not a potential associated with this process.)
the first ionization energy of He is 2372.3 kJ/mol and the second is 5250.3 kJ/mol
24.5874 eV
5250 kj/mol
Ionization potential is the energy required to remove one electron from an atom in the gaseous state. The units may be eV(electron volts) or kJ/mol. These are readily interconverted. Usually the ionization potentials for successive electrons are quoted as the first ionization potential, second ionization potential etc.
the 1st ionization energy is 403.03 kJ/mol.. since it's oxidation state is +1, you don't normally take away more than one electron so the 2nd and 3rd ionization energies are much larger and don't usually matter
This is called the ionization energy and an is different for each electron in the atom. Electrons in the outer shell (furthest from the nucleus) have the lowest ionization energy, electrons in the innermost shell (closest to the nucleus) have the highest ionization energy.
Second ionization energy of fluorine is the amount of energy needed to remove an electron from a unipositive fluorine atom (F+)to form F2+,in all the gaseous state
what or where is that in the first place and second what kind of not geek person in the right state of mond would even ask that????
Ionization potential is the energy required to remove one electron from an atom in the gaseous state. The units may be eV(electron volts) or kJ/mol. These are readily interconverted. Usually the ionization potentials for successive electrons are quoted as the first ionization potential, second ionization potential etc.
I am not sure if it is possible to get a second electron out from hydrogen, but I know how to get the IP of an electron with quantum state n=2. The equation for the ionization energy in quantum state n is En=E1/(n^2). En is the ionization in quantum state n, E1 is the ground state ionization energy, which is 13.6eV and n is the quantum state. So, if n=2, then the potential is reduced by 1/4, and the IP would be 3.40 eV.
ionization energy
It is difficult to remove electron from He than Li. LI easily loses electron and reach stable state.
the 1st ionization energy is 403.03 kJ/mol.. since it's oxidation state is +1, you don't normally take away more than one electron so the 2nd and 3rd ionization energies are much larger and don't usually matter
This is called the ionization energy and an is different for each electron in the atom. Electrons in the outer shell (furthest from the nucleus) have the lowest ionization energy, electrons in the innermost shell (closest to the nucleus) have the highest ionization energy.
Akaline metal do not exist in free state due to high level of ionization energy in them.
Second ionization energy of fluorine is the amount of energy needed to remove an electron from a unipositive fluorine atom (F+)to form F2+,in all the gaseous state
The energy needed to remove an electron from an atom (in the gaseous state) is called the IONIZATION ENERGY.
what or where is that in the first place and second what kind of not geek person in the right state of mond would even ask that????
That will depend on its ionization state. Without knowing that this question cannot be answered.
Helium has a stable (full) valence shell (1s2) which means that it will have a high ionization energy (the energy required to remove an electron). In fact, helium has the highest ionization energy of any element. However, this does not mean that helium cannot form ions. It just means that it will require a lot of energy to do so and this does not happen under normal conditions.