No, 250/3 = 83 remainder 1
3 is not a factor of 250 : the prime factors are 2 x 5 x 5 x 5 (2 x 53).
Yes, it is. Any integer can be divided by any other integer. In this case there will be a remainder, but it is divisible nonetheless.
No.
3 is not divisible by 126. 126 is divisible by 3.
3 is not divisible by 72. 72 is divisible by 3.
512 is not divisible by 3.
852 is divisible by 3.
Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.
Yes. 193 is divisible by 1 and 193. It is a prime number.
Itself and one because 193 is a prime number
There are 193 numbers in between 1 and 250 that are divisible by 2, 3, 5, or 7. Note that if you are not including 250 (so if you meant 1 - 249), then there are 192.
193 is prime. It is only evenly divisible by itself and one.
The factors of 772 are: 1, 2, 4, 193, 386, 772
3, 5, 15, 31, 93, 155, 193, 465, 579, 965, 2895, 5983, 17949, 29915.
193
64.3333
Yes, as it is only divisible by one and itself.Yes 193 is a prime number because it has only two factors which are itself and one193 is prime.
No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.No, it is divisible by 3.
193 of them are divisible by one (or more) of the given numbers.
It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.