i can't really read that reaction but! if there is an element by itself in either the reactant or the product side of the reaction QUICKLY think REDOX
because the oxidation states for ANY element is 0 by themselves and when they form compounds they either oxidize or reduce to their oxidation state
hope i helped
yes, because Hgneeds to lose 2 electrons and O needs to gain 2
yes it is a decomposition reaction which is an oxidation reduction reaction
Dissociation
a redox reaction
YES
yes
2HgO(heat) ----> 2Hg + O2
The chemical formula (NOT: equation) for mercury oxide is (there are two possibillities):Mercury(I) oxide (mercurous oxide), Hg2O.Mercury(II) oxide (mercuric oxide), HgO
the balanced equation of mercuryII oxide HgO undergoes a chemical change to form mercury and oxygen is given as .2HgO(s) --> 2Hg(l) + O2(g)The reaction is a redox reaction. Mercury (II) is reduced to zero charge. Oxygen is oxidized to zero charge.Molecule: HgO(s)
2HgO → 2Hg + O2 Mercury (II) oxide → Mercury (II) + Oxygen
"Mercuric fulminate, HgC2N2O2 ... (is) almost insoluble in cold water and requiring 130 times it weight of boiling water for solution. It may be heated to 180° C. before exploding, and the explosion so brought about is much milder than that produced by percussion." NOTE: Water boils at 100° C. http://en.wikisource.org/wiki/1911_Encyclop%C3%A6dia_Britannica/Explosives
Mercuric oxide is a compound not a reaction.
2HgO --> 2Hg + O2 is a decomposition reaction, in which Mercury oxide is decomposed into the element mercury and oxygen gas. A decomposition reaction is one in which a more complex substance is broken down into its simpler components.
2HgO (s) --> 2Hg(l) + O2 (g)
Mercuric oxide will decompose into elemental Mercury and gaseous oxygen
2HgO(heat) ----> 2Hg + O2
2HgO(s) + heat ---> 2Hg + O2
The coefficient for oxygen is 1, and so is not written. The equation is already balanced.
The chemical formula (NOT: equation) for mercury oxide is (there are two possibillities):Mercury(I) oxide (mercurous oxide), Hg2O.Mercury(II) oxide (mercuric oxide), HgO
2HgO------->2Hg+O2
the balanced equation of mercuryII oxide HgO undergoes a chemical change to form mercury and oxygen is given as .2HgO(s) --> 2Hg(l) + O2(g)The reaction is a redox reaction. Mercury (II) is reduced to zero charge. Oxygen is oxidized to zero charge.Molecule: HgO(s)
2 molecules of mercuric oxide yields 2 atoms of mercury and 2 of oxygen.
2HgO → 2Hg + O2 Mercury (II) oxide → Mercury (II) + Oxygen