0
What else can I help you with?
What is the equation for the decomposition of mercury 2 oxide?
The decomposition of mercury(II) oxide (HgO) can be represented by the following equation: 2HgO(s) -> 2Hg(l) + O2(g).
A chemist hypothesizes that mercury oxide will undergo a decomposition reaction if it reaches a certain temperature When the chemist designs his experiment what should be the only independen?
The only independent variable should be the temperature at which the mercury oxide is heated. This variable will be manipulated by the chemist to determine its effect on the decomposition of mercury oxide.
What are the products of the decomposition of mercury oxide?
When heated, mercury oxide decomposes into mercury and oxygen gas. This reaction can be represented by the following equation: 2HgO(s) → 2Hg(l) + O2(g).
In figure 19 the endothermic reaction that breaks downs mercury (II) oxide into mercury and oxygen can be classified as a reaction.?
The endothermic reaction that breaks down mercury (II) oxide into mercury and oxygen is classified as a decomposition reaction. In a decomposition reaction, a single compound breaks down into two or more simpler substances. In this case, mercury (II) oxide decomposes into mercury and oxygen when heat is applied to the system.
When heatedmercury(II) oxide reacts to mercury and oxygen?
When heated, mercury(II) oxide decomposes into mercury and oxygen gas. This is a chemical reaction where mercury(II) oxide undergoes thermal decomposition. The balanced chemical equation for this reaction is: 2HgO(s) → 2Hg(l) + O2(g)
Is copper oxide a reactant or product?
It can be either depending on the reaction. It can be a product of electrolysis of copper with sulfuric acid, or an acid base reaction of copper hydroxide and sulfuric acid. It can react with metals such as zinc.
What is the equation for the decomposition of mercury 2 oxide?
The decomposition of mercury(II) oxide (HgO) can be represented by the following equation: 2HgO(s) -> 2Hg(l) + O2(g).
A chemist hypothesizes that mercury oxide will undergo a decomposition reaction if it reaches a certain temperature When the chemist designs his experiment what should be the only independen?
The only independent variable should be the temperature at which the mercury oxide is heated. This variable will be manipulated by the chemist to determine its effect on the decomposition of mercury oxide.
How can you separate mercury oxide?
Mercury oxide can be separated by heating it to a high temperature, which leads to the decomposition of the compound into its elements: mercury and oxygen. The mercury vaporizes and can be collected, while the oxygen is released as a gas.
What needs to be added to balance the equation for the decomposition of mercury oxide?
its already balanced
What are the products of the decomposition of mercury oxide?
When heated, mercury oxide decomposes into mercury and oxygen gas. This reaction can be represented by the following equation: 2HgO(s) → 2Hg(l) + O2(g).
In figure 19 the endothermic reaction that breaks downs mercury (II) oxide into mercury and oxygen can be classified as a reaction.?
The endothermic reaction that breaks down mercury (II) oxide into mercury and oxygen is classified as a decomposition reaction. In a decomposition reaction, a single compound breaks down into two or more simpler substances. In this case, mercury (II) oxide decomposes into mercury and oxygen when heat is applied to the system.
When heatedmercury(II) oxide reacts to mercury and oxygen?
When heated, mercury(II) oxide decomposes into mercury and oxygen gas. This is a chemical reaction where mercury(II) oxide undergoes thermal decomposition. The balanced chemical equation for this reaction is: 2HgO(s) → 2Hg(l) + O2(g)
Does mercuric oxide decompose on heating?
Mercuric oxide decomposes upon heating to give off mercury and oxygen.
In iron sulphide plus oxygen gives iron oxide plus sulfur dioxide is iron a reactant or product?
There is no elemental iron (Fe) involved in this reaction, neither as reactant (iron sulphide -FeS- plus oxygen are) nor as product (iron oxide (FeO) plus sulphur dioxide are)
When binary compound is theonly reactant what are the products most likely to be?
When a binary compound is the only reactant, it will likely undergo decomposition to form its constituent elements. For example, when water (H2O) is the reactant, it can decompose to form hydrogen gas (H2) and oxygen gas (O2).
How does the maximum yield of products for a reaction depend on the limiting reactant?
The best way to answer this question is with an example. Using Calcium oxide reacting with hydrochloric acid, the reaction formula is: CaO + 2HCl ----->CaCl2 + H2O The molecular weight for Calcium Oxide is 56, for Hydrochloric acid is 26.5 and for calcium chloride 110. If you start with only 56g of Calcium oxide but say 10000g of hydrochloric acid, the maximum yield of the product calcium chloride can only ever be 110g. It does not matter how much hydrochloric acid is added. The limiting reactant in this example is the calcium oxide.
