It can be either depending on the reaction. It can be a product of electrolysis of copper with sulfuric acid, or an acid base reaction of copper hydroxide and sulfuric acid.
It can react with metals such as zinc.
Copper (I) Oxide or Cuprous Oxide
CuO = Cupric Oxide Cupric = Cu2+ and is not Cu The correct answer would be CuO = Copper Monoxide Copper (II) oxide is the name of the compound CuO.
When copper reacts with oxygen in the air, it forms copper oxide. This reaction results in a brownish-black layer of copper oxide being formed on the surface of the copper, giving it a dull appearance. Copper oxide is not harmful and can be easily removed by cleaning the copper surface.
When copper is burned in the presence of air, it forms copper oxide. Copper oxide can exist in different forms, such as copper(I) oxide (Cu2O) or copper(II) oxide (CuO), depending on the conditions of the reaction.
When copper and oxygen react, they combine to form copper(II) oxide. This chemical reaction involves the transfer of electrons from copper to oxygen, resulting in the formation of the compound CuO. Copper(II) oxide is a black solid.
For copper, it is an element. It could be both reactant and product. While purifying copper will be the product. But copper would be the reactant in case of preparing hydrogen or copper sulphate salts.
For copper, it is an element. It could be both reactant and product. While purifying copper will be the product. But copper would be the reactant in case of preparing hydrogen or copper sulphate salts.
Using the given masses, calculate the moles of each reactant. The limiting reactant will be the one that produces the least amount of product, which is copper. Convert the moles of copper to moles of copper (II) oxide using the balanced chemical equation. Then, convert the moles of copper (II) oxide to grams to find the mass produced.
When excess copper oxide is added to dilute sulfuric acid, the excess copper oxide will react with the acid to form copper sulfate and water. The reaction will continue until all the copper oxide is used up. This is known as a limiting reactant situation, where one reactant is completely consumed before the other.
Copper reacts with oxygen in the air to form copper oxide.
2Cu + O2 ==> 2CuO product is copper(II) oxide4Cu + O2 ==> 2Cu2O product is copper(I) oxide
When the product is with oxygen it will be copper oxide CuO. If it is with nitrogen it is copper nitrate.
When copper is heated, it undergoes oxidation and forms copper oxide as the main product. If the heating is carried out in the presence of oxygen, copper oxide (CuO) is formed. If the oxygen is limited, copper(I) oxide (Cu2O) can also be formed.
Since there are two valence states for copper, Cu+ and Cu2+, there are two compounds formed from copper and oxygen:Copper (I) Oxide = Cu2O (equation: 4Cu + O2 --> 2Cu2O)Copper (II) Oxide = CuO (equation: 2Cu + O2 --> 2CuO)
Calcium hydroxide can be either a product or a reactant, depending on the chemical reaction in question. For example, in the reaction between calcium oxide and water, calcium hydroxide is formed as a product. Conversely, it can also act as a reactant in reactions where it participates in forming other compounds.
There is no elemental iron (Fe) involved in this reaction, neither as reactant (iron sulphide -FeS- plus oxygen are) nor as product (iron oxide (FeO) plus sulphur dioxide are)
The best way to answer this question is with an example. Using Calcium oxide reacting with hydrochloric acid, the reaction formula is: CaO + 2HCl ----->CaCl2 + H2O The molecular weight for Calcium Oxide is 56, for Hydrochloric acid is 26.5 and for calcium chloride 110. If you start with only 56g of Calcium oxide but say 10000g of hydrochloric acid, the maximum yield of the product calcium chloride can only ever be 110g. It does not matter how much hydrochloric acid is added. The limiting reactant in this example is the calcium oxide.