N2 + 3H2 --> 2NH3 is possible according to Dalton's theory. It also is probable and is the equation for the Haber process which is used to produce ammonia from nitrogen and hydrogen. You can read about the Haber process by referring to the related link below, if you are interested.
They don't spontaneously react, but that's essentially the reaction in the Haber process.
I'm not quite sure
Use the Equilibrium formula..
Nitrogen(N2) + Hydrogen(3H2) (reversible reaction chemical symbol) Ammonia(2NH3)
N2 + 3H2 Right arrow. 2NH3
6
s is positive and g is negative at low temperatures only
2NH4Cl + Na2CO3 --> 2NH3 + CO2 + H2O + 2NaCl
There weren't any answer choices provided. But I found an example and if this is the example N2(g) plus 3H2(g) equals 2NH3(g) then the answer is none of the above. The question is messed up and all of the answer choices are the same.
neutralisation reaction
It is a neutralistion reaction.
2NH3 is the product of N2+3H2
Four ammonia plus five oxygen molecules yields 4 nitrous oxide plus six water.
3h2 + n2 ==> 2nh3
s is positive and g is negative at low temperatures only
How do you solve 4y plus x equals 8
2NH4Cl + Na2CO3 --> 2NH3 + CO2 + H2O + 2NaCl
-2 plus 5 equals +3
Not enough information to solve
2NH3 + 2NA = 3H2 + NA3N2
There weren't any answer choices provided. But I found an example and if this is the example N2(g) plus 3H2(g) equals 2NH3(g) then the answer is none of the above. The question is messed up and all of the answer choices are the same.
neutralisation reaction
It's a chemical reaction.