The rusting of iron is given by the balanced equation:4Fe + 3O2 --> 2Fe2O3
4Fe(s) + 3O2(g) ===> 2Fe2O3(s)
The basic process to extract iron from ores is to oxidize the ore into iron oxides (such as FeO, Fe2O3, etc.). The iron oxides are melted and mixed with charcoal or coke (carbon from purified coal). The reaction for Fe(III)oxide is: 2Fe2O3 + 3C ---> 4Fe + 3CO2 Typically the molten product was pored into ingots known as pig iron.
Whoops, that came out incorrectly. Let me try to do it again... Which of the following is an example of an acid-base Reaction? A. HCl + NaHCO3 ---> NaCl + CO2 + H2O B. O2 + 2PBr3 ---> 2POBr3 C. 4Fe + 3O2 ---> 2Fe2O3 D. Zn + 2HCl ---> ZnCl2 + H2
The chemical formula is written as:4Fe + 3O2 2Fe2O3. Your welcome
4Fe + 3O2 --> 2Fe2O3
Assuming you mean 2FeO3+3C ---> 4Fe+3CO2, yes, it is balanced.
coke is used to reduce oxides in the metal eg 2Fe2O3 + 3C -> 4Fe + 3CO2
The formula for iron (III) oxide is FeCl3, whether the formula is in a balanced equation or anywhere else where the formula is properly used.
O does not exist by itself. The balanced equation would be 4Fe + 3O2 --> 2Fe2O3
The rusting of iron is given by the balanced equation:4Fe + 3O2 --> 2Fe2O3
4Fe + 3O2 -> 2Fe2O3
There are two possible equations as iron is capable of forming two different oxides: O2 + 2Fe --> 2FeO 3O2 + 4Fe --> 2Fe2O3
2(Fe2O3)+3C ==> 4Fe + 3CO2
4Fe + 3O2 2Fe2O3
A basic equation for the formation of rust is 4Fe + 3O2 --> 2Fe2O3
No, it is the oxidation of iron (4Fe(s) + 3O2) to form iron oxide(2Fe2O3).