We need to get both equations into slope-intercept form. If they are parallel, they will have the same slope. If they are perpendicular, they will have slopes that when multiplied equal -1. (unless one line is horizontal and the other vertical)
3x+2y=5
2y=5-3x
y=(-3/2)x+(5/2)
3x+2y=9
2y=9-3x
y=(-3/2)x+(9/2)
The two lines are parallel, since both slopes are equal to (-3/2).
It is not one, but they are two perpendicular lines.
y equals -1/3x plus 4/3
The two lines are: 2x+4y=2 4x+2y=5 Le't write them in slope intercept form 4y=-2x+2 or y=-1/2+1/2 AND 2y=-4x+5 or y=-2x+5/2 Now we use the fact the parallel lines have the same slope. One line here has slop =1/2 and the other has -2. Next if lines are perpendicular the product of the slopes is -1. This is not the case here either. So the answer is NEITHER!
(3, 2)
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No. They are parallel.
The second equation works out as y = -1/2x+6 therefore it is perpendicular
One single line is never parallel or perpendicular. Those words tell you somethingabout the relationship between two lines.
perpendicular
4x+2y = 6 2y = -4x+6 y = -2x+3 Perpendicular slope is 1/2
They are parallel because the slope has the same value in both equations.
parallel
The lines are mutually perpendicular.
They are parallel lines.
The lines are parallel.
It is not one, but they are two perpendicular lines.
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