Out of that list, 2, 3 and 6

42 is divisible by 2, 3 and 6 but not by 9.

42 is divisible by: 1 2 3 6 7 14 21 and 42.

Its digits add up to a multiple of 3.

126 is divisible by 2, 3 and 9 but not the other 2 126/2= 63 126/3= 42 126/9= 14

it is divisible by all three

It is divisible by 2 and 3. It isn't divisible by 5 and 10.

Yes, 3 x 14 = 42. It is also divisible by these numbers: 1 2 3 6 7 21 and 42.

The smallest number that can be divisible by these three numbers is 42. If 42 is multiplied by 2, 3, 7, or any number divisible by only one of those numbers then that number as well will be divisible by 2, 3, and 7.

Yes. 126 divided by 3 is 42 42 is also divisible by 3. 42 ÷3 = 14 The prime factors of 126 are 2, 3, 3, and 7.

42 is divisible by 2, 3, 6, & 7

It is evenly divisible by 2 and 10 but not by 3 and 9.

Yes, it is divisible by 2, 3 and 9, but is not exactly divisible by 5 or 10.

9 is divisible by 3 10 is divisible by 2, 5 and 10. Everything else, no.

2, 3, and 6 . . . . . yes 4, 5, 9, and 10 . . no

20 is divisible by 2, 5 and 10. It is not exactly divisible by 3 or 9.

1, 2, 3, 6, 7, 14, 21 and 42.

It is divisible by 2, 5 and 10, but not 3 and 9.

No , the answer would be 42 and 2/3

29,178 is divisible by 2, 3 and 9, not by 5 or 10.

It is divisible by 2 & 3. It is not divisible by 5, 9 & 10. 534 is even → divisible by 2 5 + 3 + 4 = 12 → divisible by 3 534 does not end in 0 or 5 → not divisible by 5 5 + 3 + 4 = 12 → not divisible by 9 534 does not end in 0 → not divisible by 10

1, 2, 3, 6, 7, 14, 21, 42.

It is evenly divisible by 2 and by 3.

Because 410 ends in 0, it is divisble by 10. To determine if it's divisible by 6, it needs to be divisible by 2 and 3. it is divisible by 2, as it is even, but is not divisible by 3;

It is divisible by 2, 5 and 10 but not the rest.

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