slightly
slightly
It actually reacts with AgCl to produce NaCl (which is soluble), and some Na3[Ag(S2O3)2]complexes which are also soluble in water.
It would come out to Ag^+ + Cl^- = AgCl Remember solubility rules nitrate and Ca both are soluble therefore they are not in the final equation.
Chloride ion (Cl-) will not precipitate silver ion (Ag+) because silver chloride (AgCl) is insoluble and will not form a precipitate.
The oxidation number of Ag in AgClO4 is +1, as it is a common oxidation state for silver in compounds. The oxidation number of Cl in AgClO4 is +7, as it is in the ClO4- ion which has a total charge of -1.
soluble
One mole of chloride (Cl-) to one mole of Ag+ ions: Cl- + Ag+ --> AgCl(s)
The oxidation number of Ag in AgCl is +1. AgCl is an ionic compound where Cl has an oxidation number of -1, so for the compound to be neutral, the oxidation number of Ag must be +1.
Ag, Hg, Pb
in the AgCl molecule two atoms present one is Ag (i.e.Ag in +1oxidation state) & another is Cl atom(Cl in -1).
A linear ionic bond is formed
The oxidation number of silver (Ag) in AgCl is +1. This is because chlorine (Cl) has an oxidation number of -1 in most compounds, so the overall sum of the oxidation numbers must be zero for a neutral compound like AgCl.