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Glucose is formed using Covalent Bonding. This is proven because none of the elements that form Glucose are metals (Carbon is a Gas, Hydrogen is a Gas and Oxygen is a Gas). Ionic Bonding is the transfer of elections from METAL to NON-METAL. If you are drawing a diagram of the Glucose (to show how many electrons are shared with each element), simply draw a ring of the Carbons. Then, draw 1 Hydrogen connected to the Carbons, by themselves. Finally, draw an Oxygen connected to each of the Carbons, with a further Hydrogen connected to each of the Oxygens. Now, with Glucose, you have 12 Hydrogens that all need another Electron to complete it's outmost shell. Hydrogen, only having 1 proton (therefore having 1 electron), needs just one because the stable form of electrons is always 2,8,8. Hydrogen is also in Group 1, so it only has 1 shell. The 6 Hydrogens connected directly to the Carbons will share it's only electron with the Carbon. The Carbon, in turn, will share 1 electron back, leaving the Carbon with 3 electrons that it can share and it will also need 3 more electrons to complete it's outer shell. The 6 Hydrogens connected to the Oxygens will also share it's only electron with the Oxygen. The Oxygen will also share 1 electron with the Hydrogen. At this stage, the Hydrogens will all have a complete outer shell. Now, the Oxygen needs 1 electron to complete it's outer shell and the Carbon needs 3 to complete it's outer shell. So, simply share 3 electrons from each Oxygen with the Carbon and allow the Carbon to share a single electron. You will find that every atom has a full outer shell. It does get a bit confusing, I know. But you've just got to remember that Ionic Bonding is the TRANSFER of Electrons from METAL to NON-METAL. If a Metal is not present, it is not Ionic Bonding.

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15y ago
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14y ago

All isomers having formula C6H12O6 are covalent compounds but show some ionic character (polar bonds).

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10y ago

Covalent bonded

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Q: Is C6H12O6 an ionic or covalent bond?
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