The ion CH3COO- (acetate ion) is mildly basic
The compound is ethanoic acid, and it is not a base.
Well, the first step in Fischer Esterification is protonation of the carboxylic acid.
The conjugate acid is the acetic acid, CH3COOH.
NaHCO3 is a weak base, with a conjugate acid of H2CO3+.
Acetic acid reacts with a base to form water and a salt called sodium acetate. This reaction is a neutralization reaction where the hydrogen ion from the acid combines with the hydroxide ion from the base to form water.
The compound is ethanoic acid, and it is not a base.
Acetate is CH3COO because it is the conjugate base of acetic acid (CH3COOH). When acetic acid loses a proton (H+), it forms the acetate ion (CH3COO-).
Well, the first step in Fischer Esterification is protonation of the carboxylic acid.
The conjugate acid is the acetic acid, CH3COOH.
NaHCO3 is a weak base, with a conjugate acid of H2CO3+.
Acetic acid reacts with a base to form water and a salt called sodium acetate. This reaction is a neutralization reaction where the hydrogen ion from the acid combines with the hydroxide ion from the base to form water.
H2S and HS-
In general, a buffer system can be represented by writing a salt followed by slash and an acid or conjugate base followed by slash and an acid like salt/acid or conjugate base/acid. Thus, the sodium acetate-acetic acid buffer system can be written asCH3COONa/ CH3COOH or CH3COO-/CH3COOHSimilarly, ammonia-ammonium chloride buffer system can be represented asNH3 / NH4+Note that NH4+ is an acid and NH3 is a conjugate base according to Lewry-Bronsted concept.
No. Acetate is the anion (negative ion) derived from acetic acid. Acetic acid is CH3COOH. Acetate is CH3COO-. Acetate ions exist in minute concentrations in a solution of acetic acid and can also be produce by neutralizing acetic acid with a base.
The formula for acetate is CH3COO- or C2H3O2-. It is the conjugate base of acetic acid.
Each cationic acid HA+, when it donates ONE proton H+, will form its conjugated base A of the acid HA+. (Example: NH4+ ammonium, acid NH3 ammonia, base)Each neutral acid HA, when it donates ONE proton H+, will form its conjugated base A- of the acid HA. (Example: CH3COOH acetic acid CH3COO- acetate, base)Each anionic acid HA-, when it donates ONE proton H+, will form its conjugated base A2- of the acid HA-. (Example: HS- (mono)hydrogen sulfide, acid S2- sulfide, base)Each anionic base HA-, when it adopts ONE proton H+, will form its conjugated acid H2A of the base HA-. (Example: HS- mono-hydrogen sulfide, base H2S di-hydrogen sulfide, acid)Each anionic base A-, when it adopts ONE proton H+, will form its conjugate acid HA of base A-. (Example: CH3COO- acetate, base CH3COOH acetic acid)Each neutral base A, when it adopts ONE proton H+, will form its conjugate acid HA of base A-. (Example: NH3 ammonia, base NH4+ ammonium, acid)
Ca(CH3COO)2Neutral as the is the calcium salt of acetic acid.