p-nitro phenol has a symmetric structure as compare to o-nitro phenol so it has higher dipole moment or polarity so is more soluble.
Example: some hydroxides are suluble in water but other aren't soluble.
I would replace that word 'most' with 'totally' ... ethanol and water mix in all proportions.
Mentol (so with an 'O' in it) is an essential oil in mint-like extracts, which is hardly soluble in water.
Ca, Al, Si, Na, K, Mg, Fe, O • •And we pass lots of hot water and sulfur through it.
p-nitro phenol has a symmetric structure as compare to o-nitro phenol so it has higher dipole moment or polarity so is more soluble.
yes it is soluble!! :O
No hexane is insoluble in water. "Like dissolves like" meaning the more alike (chemically) two things are the more likely they will be soluble in each other. Hexane and water are just chemically too different. Hexane has a very low solubility in water, just a few mg/l. For most purposes it can be considered insoluble. However in one very important aspect it must not be considered insoluble. The vapour pressure of hexane above water containing just a few mg/l is as great as above pure hexane and can lead to explosive atmospheres.
Example: some hydroxides are suluble in water but other aren't soluble.
Firstly add water to the compound and check if it is soluble. Secondly add Tincture of iodine(iodine tincture). Lastly add acetic acid. All these steps need to be performed separately. For the compound to be magnesium sulfide, the test results must as below: Water : Insoluble Iodine Tincture : Yellow Acetic Acid : Fizzy
I would replace that word 'most' with 'totally' ... ethanol and water mix in all proportions.
Yes, all phenols and naphthols (i.e., phenolic -OH group) are soluble in alkalis.
The solubility of oxygen in water at 20 oC and 760 mm Hg is 9,1 mg/L.
Mentol (so with an 'O' in it) is an essential oil in mint-like extracts, which is hardly soluble in water.
Sucrose is completely soluble in water even near O 0C.
Ca, Al, Si, Na, K, Mg, Fe, O • •And we pass lots of hot water and sulfur through it.
Yes, I suppose so looking at the stable, quite ionic, polar (S-O) group in it:CH2=CHCH2-S+(-O-)-S-CH2CH=CH2