They are both from the same group, yes. But F is above Cl so it means that the F's valence shell is nearer the nucleus (or at "lower level") than the valence shell in Cl, which causes F to have more effective nuclear charge.
This fact explains the more electron affinity* in F in relation to Cl and therefore F is more reactive.
* - electron affinity refers to a free atom. electronegativity refers to an atom in a molecule.
C-Cl bonds are easier to break than C-F bonds.
in Cl the resonance occurs from 3p orbitals but in F resonance occurs from 2p orbitals due this reason F increase electron density in conjugate base more as compare to Cl .
Cl and F
Cl2, O has atomic number 8, Cl has atomic number 17 so in OCl- , there are 26 electrons. ClF has the same number of electrons, Cl atomic number 17, F atomic number 9- this is an interhalogen, chlorine monofluoride. A quick way is to look for an atom with an atomic number one higher (that's to compensate for the electron) than either Cl or O. You can ignore Cl as the atom with atomic number 18 is argon a noble gas- one higher than Cl is F.
The H-F bond is more polar than the H-I bond because F (fluorine) is more electronegative than I (iodine). It thus attracts the shared electrons more than does the I, making it a more polar bond.
As-F bonds should be more polar, because fluorine is the most electronegative of all elements.
P-S , H-F, P-Cl
F is the stronger base because it is bigger than Cl
No, H-F is more polar because fluorine, F, is more electro-negative than chlorine, Cl.
C-Cl bonds are easier to break than C-F bonds.
in Cl the resonance occurs from 3p orbitals but in F resonance occurs from 2p orbitals due this reason F increase electron density in conjugate base more as compare to Cl .
bond energy (in kJ/mol) F-F:158 Cl-Cl: 244 Hence, in order of decreasing bond strength: Cl-Cl => => (F-F) => Fluorine is an anomaly. Bond strength decreases from chlorine to iodine as down the group, the atomic size becomes larger and thus the valence electron orbitals become more diffused, causing the overlap of orbitals to become less effective. Therefore the halogen-halogen bond becomes weaker. Fluorine is an exception due to its extremely small size. The F-F bond length is so short that the lone pairs of electrons on the fluorine atoms repel each other and weakens the F-F bond. I hope that answers your question.
Neon
the f-p-f bond angle is 120the cl -p-cl bond angle is 180and the f - p - cl bond angle is 90
All halogen elements have 7 valence electrons (group 17): F, Cl, Br, I, At.
CClF3 is polar because it is asymmetrical. Imagine the central carbon atom inside a tetrahedrom with the base of 3 flourines and the top of a chlorine. Since the flourines are more electronegative than the chlorine (F is higher in the VIIA column than Cl), they will get the bigger share of the electrons, and Cl less. So the fluorine side is d- and the chlorine side d+. It is hard to draw on this, but this is my best: Cl d+ C F F F d-
You mostly want the temparuture at 75 F. This is when they will be the most active. Never get it more than 80 F. Never get it less than 60 F