It is not a two player game, but there are more than one players that you can battle with.
No.
Single Player with a Party.
FFXI is the only Online Game
FFIX is Multiplayer etc
4-player, and, although it can be played single player, it was meant to be played by as many players as possible.
You can't get Tidus in Final Fantasy X-2 to begin with.
The Password is ACTW use them in capital letters only....... best of luck..............
here they are in order: Final Fantasy: Legend of the Crystals Final Fantasy: The Spirits Within Final Fantasy: Unlimited (TV Series) Final Fantasy VII Advent Children Last Order: Final Fantasy VII
by clicking the save button (.)(.) -__-
I would Suggest you play the previous games but you don't have to. All Final Fantasy games ( except X and X2) have a differant story completely independent of the others. the only thing that will be the same is a couple of characters Names (eg Cid, Wedge and Biggs). If your going to play FFX2 then i suggest you play X as it is a sequal.
As X-2 is now a somewhat old game, it may be a bit hard to find, but i'd recommed checking gamestop or any local gamestore. Then again, you've got the sure-fire eBay or amazon.
First, it is important to regroup, so I am going to rearrange this equation: (x4 - 7x2 - 18 - 3x3 + 27x I can now factor the first three terms and the last two terms: (x4 - 7x2 - 18) becomes (x2 - 9)(x2 + 2) -3x3 + 27x becomes -3x(x2 - 9); so the new equation looks like: (x2 - 9)(x2 + 2) - 3x(x2 - 9) From here, factor out what is common, in this case- x2- 9. Therefore, you will have (x2 - 9)(x2 + 2 - 3x), which can be rearranged to (x2 -9)(x2 - 3x + 2). Further factoring reveals (x + 3)(x - 3)(x - 1)(x - 2) as the final answer.
Simplifying x2 + -2x + -63 Reorder the terms: -63 + -2x + x2 Factor a trinomial. (-7 + -1x)(9 + -1x) Final result: (-7 + -1x)(9 + -1x)
two/ x2
The question is ambiguous and two possible answers are given below: 2x2 - x2 = x2 or (2x)2 - x2 = 4x2 - x2 = 3x2
There are none. Those two curves do not intersect.
Two points: (x1, y1) and (x2, y2), Then formula would be: y2 - y1 (over) x2 - x1