No.
H2PO4- is called dihydrogen phosphate ion. It is the conjugate base of phosphoric Acid H3PO4 and the conjugate acid of monohydrogen phosphate ion HPO42-
Yes, during acidosis the body binds free protons (which bring about acidosis) to certain bases that cannot be reabsorbed by the kidney.
2 of these molecules that are excreted proton bound molecules are H2PO4 (Dihydrogen Phosphate) and NH4 (ammonia). By binding the protons to molecules that cannot be reabsorbed they are excreted in the urine and the pH of the body returns to normal.
To further counter acidosis the body increases reabsorption of bicarbonate ions in the proximal convoluted tubule to act as buffers - these bind to protons in the blood and neutralise them.
This chemical formula is Sr(H2PO4)2.
It has 4 bonding pairs and no lone pairs so it has a tetrahedral shape.
The question is phrased incorrectly... it is HPO4 not HOP4. The answer is H2PO4 in the urine in alkalosis.
PO2(OH)2 is the same as H2PO4^- (note the negative charge). It would be dihydrogen phosphate.
The solubility of Ca(H2PO4)2·H2O is approx. 20 g/L at approx. room temperature.
In H2O the conjugate base is H2PO4-, being conjugated to the acid H3PO4. As well: H3PO4 is conjugated acid to the base H2PO4-.
phosphate
5 !
h2po3
PO4 has a charge of -3 (Al is +3
dihydrogen phosphate
Dihydrogen Phosphate
There are three protolysis steps:H3PO4 ---> H+ + H2PO4-H2PO4- ---> H+ + HPO42-HPO42- ---> H+ + PO43-
Formula: BaHPO4
dihydrogen phosphate --> PO4(-3) + 2H --> H2PO4(-1) magnesium dihydrogen phosphate --> Mg(2) + H2PO4(-1) --> Mg(H2PO4)2
PO43-
HPO4 2-