yes
Ionic
To calculate the percent ionic character of a bond, you can use the equation: % Ionic Character = (1 - exp(-0.025*dipole/bond distance))100. Plugging in the values given, you would get % Ionic Character = (1 - exp(-0.0250.380/161))*100. Solving this will give you the percent ionic character of the bond.
This is a ionic bond.
Oh, dude, the percent ionic character of a bond is determined by the difference in electronegativity between the two atoms involved. In the case of the HI bond, hydrogen has an electronegativity of 2.20 and iodine has an electronegativity of 2.66. So, the percent ionic character of the HI bond is around 20.5%. But hey, who's really keeping track, right?
Ozone forms covalent bonds. Ionic bonds form only between metals and non-metals.
ionic bond
The percent ionic character of a bond is calculated using the difference in electronegativity of the atoms involved. In the case of the Br-F bond, bromine has an electronegativity of 2.96 and fluorine has an electronegativity of 3.98. The percent ionic character of the Br-F bond is 38.5%.
It is ionic
Ionic bonds
This is an ionic bond.
The ionic bond has the most ionic character.
Don't listen to who said that i was doing a quiz and it was wrong the real answer is an induced charge.