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Is NH2OH basic or acidic?
There is no such compound, NH3 is basic and somethimes written as aquous solution of NH4OH
What is the conjugate acid of NH2OH?
The conjugate acid of the base NH2OH (hydroxlyamine) is NH3OH^+
What is the pH of NH2OH?
It all depends on the molarity of the solution.
What is the polarity of NH2OH?
polar
Is NH2OH IS IONIC OR COVALENT?
NH2OH is a covalent compound. It contains covalent bonds formed between nitrogen and hydrogen atoms.
What is the molecular geometry of NH2OH?
Tetrahedral
How do you convert cyclohexanol to nylon-6?
using cu and NH2OH at 250 C
How do you prepare a 0.5 M hydroxylammonium chloride NH2OH-HCl solution?
To prepare a 0.5 M hydroxylammonium chloride solution, you would dissolve the appropriate amount of NH2OH-HCl in a specific volume of water. Calculate the moles of NH2OH-HCl needed (Molarity x Volume) and dissolve it in water to make the desired volume. Always remember to handle the compound with care due to its toxicity and reactivity.
What is the oxidation state of an individual nitrogen atom in NH2OH?
This answer is -1.To find this answer:Oxygen has an oxidation number of -2.Hydrogen has an oxidation number of +1, and there are 3 of themyou want to get the oxidation numbers to add up to 0, so it would be neutral.-2 + 3(+1) = +1Now, to get this to equal zero, it means that N has to be -1.
What is the oxidation number of N in NH2OH?
The oxidation number of N in NH2OH is -1. This is because each hydrogen atom has an oxidation number of +1, and oxygen usually has an oxidation number of -2. Since the overall molecule has a neutral charge, nitrogen must have an oxidation number of -1 to balance out the charges.
Consider the reaction nh2oh aq plus h2ol nh3oh plus aq plus h3o plus aq if ka equals 1.5 x 10-6 for nh3oh plus what is kb for nh2oh kw equals 1.0 x 10-14 at this temperature?
6.6 x 10-9
Consider the reaction nh2ohaq h2ol nh3oh aq h3o aq if ka 1.5 x 10-6 for nh3oh what is kb for nh2oh kw 1.0 x 10-14 at this temperature?
To find the (K_b) for NH2OH, you can use the relationship (K_w = K_a \times K_b). Solving for (K_b), we have (K_b = \frac{K_w}{K_a} = \frac{1.0 \times 10^{-14}}{1.5 \times 10^{-6}} = 6.67 \times 10^{-9}). So, the (K_b) for NH2OH at this temperature is (6.67 \times 10^{-9}).
