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While some feel that Thevenin's (commonly misspelled as Thevinin's) Theorem is made invalid by dependent sources, rather than independent sources, most hold his theories valid. This is largely due to the superposition theorem, proven by combining Thevenin's theorem with Norton's.

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Q: Is Thevinin's theorem valid with the presence of dependent sources?
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Why you use linear network in thevinins theorem?

Because Thevenin does not work for a nonlinear network, e.g. a battery in series with a diode and resistor.


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Because millman's is used in parallel ckt of impedances and voltage sources


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If this is an independent current source, it has to be disconnected.Independent voltage sources are replaced by a short-circuit.More about this at (see Related links):MasteringElectronicsDesign.com: How to Apply Thevenin's Theorem - Part 1, Solving Circuits with Independent SourcesandMasteringElectronicsDesign.com: How to Apply Thevenin's Theorem - Part 2. Nested Thevenin Sources Method


How you calculate the polarity of voltage source across the resistor when two voltage sources are connected?

A: by using thevenin theorem


Where is theorem used?

In circuits with multiple sources. This allows you to analyze the effects of each source separately, which often simplifies the math.


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superposition can find the voltage and current effect of each source to a particular branch of the circuit and we can calculate the total effect of the sources to know the effect of the total sources to that branch


According to Theremins theorem any linear active network can be replaced by a single voltage source?

You are confusing "Thévenin" with "Theremin." Léon Charles Thévenin (1857-1926) developed a theorem for linear electrical networks stating that any combination of voltage sources, current sources and resistors with two terminals is electrically equivalent to a single voltage source and a single series resistor.


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