Not necessarily. The allele for colorblindness is recessive. For a female, in order to be colorblind she must have to recessive alleles for colorblindness. Example: XcXc would be colorblind. XCXc would be a carrier for colorblindness, but not colorblind. For a male, because colorblindness is a sex-linked gene, he only needs one allele to be colorblind. Example: XcY is colorblind. XCY is not colorblind.
the colorblindness is usually not activited in a female body but is usually seen in male
true and false it depends
We know that if a father is colorblind and the mother is neither colorblind nor a carrier, then the sons will not be colorblind. So, using logic, that means that the father can't cause a son to become colorblind. Process of elimination would point towards whenever a son is colorblind that it comes from the mother. A diagram explaining how colorblindness is inherited can be viewed in the related links.
If the mother is a carrier of the colorblind gene (XcX) and the father has normal color vision, the probability of their child being colorblind is 50%. This is because the child has a 50% chance of inheriting the Xc chromosome from the mother and developing colorblindness.
males dealing with colorblindness
In short, hemophilia has nothing to do with colorblindness, but YES, they could have a colorblind child if she is a carrier for the colorblindness gene. Color blindness is an X-linked trait. That means it is carried in the X chromosome, which differentiates whether a baby will be a girl or a boy. Women have two X chromosomes (XX), and men have an XY combination. If a woman is a carrier for color blindness, only one of her chromosomes will be affected (we'll call it a little "x"), and for that reason she will not be colorblind. Men, on the other hand, only have one X chromosome, so any time they carry the colorblindness gene, they will be colorblind. A woman will carry the colorblindness gene if: a. Her father is colorblind b. Any of her offpsring are colorblind She may carry the colorblindness gene if: a. Male family members (brothers, uncles, etc.) are colorblind A child inherits one chromosome from each parent. He/She will get an X chromosome from his/her mother, and an X from her father (if a girl) or a Y from his father (if a boy). So, If a woman has normal vision (assuming she does not have a family history of colorblindness), XX, and a man is colorblind, xY, they have several different chances for different offspring: Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) The short answer is that ALL CHILDREN WILL HAVE NORMAL VISION. However, all daughters will be CARRIERS, meaning they can pass colorblindness on to their children.
Take a colorblindness test from a doctor or in a book or on the internet
Yes. Because the colorblind trait is a sexlinked trait and is found in the X chromosome that is inherited from the mother, men that only have one X chromosome will develop colorblindness if the trait is found in this gene. For a woman to get it, she would need to have the colorblind gene on both x chromosomes. Therefore the girl´s dad would have to be colorblind and the mother at least a carrier.
It has to do with the slight differences in the DNA, ANSWER Colorblindness is sex linked trait. Females are XX and Males are XY. The colorblind gene is only on the X chromosome so if a male has the gene on the X chromosome then he will be colorblind. Females can have it on one X chromosome, but not the other and not be colorblind; however, they are a carrier and can pass it on. For a female to be colorblind both X chromosomes must have the gene.
Not necessarily. The allele for colorblindness is recessive. For a female, in order to be colorblind she must have to recessive alleles for colorblindness. Example: XcXc would be colorblind. XCXc would be a carrier for colorblindness, but not colorblind. For a male, because colorblindness is a sex-linked gene, he only needs one allele to be colorblind. Example: XcY is colorblind. XCY is not colorblind.
The father has to be colorblind for the daughter to be colorblind because both X chromosomes must have the colorblindness gene in females because the colorblind gene is recessive. If only the mother is color deficient, then she merely passes on the gene to one of the X chromosomes in a female. If both the mother and father are both colorblind, then both X chromosomes in the female are effected and the female is colorblind. There are two scenarios in which a daughter may be born colorblind. 1. The father is colorblind and the mother is a carrier of the colorblind gene. The daughter will be either colorblind or a carrier of the colorblind gene. 2. The father and mother are both colorblind. If this is the case, then all of the children will be born colorblind.
The probability of a colorblind child being born is 50%. This is because the male passes his Y chromosome to all his sons, and since he is colorblind, his sons will inherit the colorblind gene from him. The daughters will inherit their X chromosome from the mother and have a 50% chance of being carriers like her.