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percentage change: 113-90.7/90.7= 22.3/90.7=(0.24....x 128)+128=159.47mL
No. kPa is a measure of pressure, mL is a measure of volume.
327.45762711864406779661016949153ml
120 kP
how many moles are contained in 4.67 L sample of gas at 33 degrees celcius and 199 kpa
61ml
percentage change: 113-90.7/90.7= 22.3/90.7=(0.24....x 128)+128=159.47mL
Boyle's Law: p*V = constant for 1. same amount of gas and 2. at same temperatureThis will do: V = (98.4*0.725)/142= 0.502 L
More pressure means less volume. Calculate the ratio of pressure, then divide the 4.2 liters by that ratio.This assumes: * That the temperature doesn't change. * That the gas behaves like an ideal gas.
No. kPa is a measure of pressure, mL is a measure of volume.
327.45762711864406779661016949153ml
120 kP
3.8 kPa
how many moles are contained in 4.67 L sample of gas at 33 degrees celcius and 199 kpa
The pressure is 68,3 kPa.
The volume you would expect the gas to occupy if the pressure is increased to 40 kPa would be 50 liters.
20.26 kPa is 0.2 ATM