Well if you are familiar with calculus the projection of acceleration vector a(t)on to the Tangent unit vector T(t), that is tangential acceleration. While the projection of acceleration vector a(t) on to the normal vector is the normal acceleration vector. Therefore we know that acceleration is on the same plane as T(t) and N(t). So component of acceleration for tangent vector is (v dot a)/ magnitude of v component of acceleration for normal vector is sqrt((magnitude of acceleration)^2 - (component of acceleration for tangent vector)^2) sorry i can't explain it to you more cause I don't have mathematical symbols to work with
v = a t a = v / t Bonus: t = v / a
If the true value is t and the calculated or measured value is v then absolute error = |v - t|, the absolute value of (v - t).If v >= t then the absolute value is v - tif v
Well, V=s/tso, V/t = (s/t)/tor V/t = s/t * 1/tso, V/t= s/(t^2). It is equal to acceleration.
T. V. Padma was born in 1969.
map projection
An image formed by a convex lens is described by the lens equation 1/u+1/v=1/f, where u is the distance of the object from the lens, v is the mage distance from lens and f is the focal length of the mirror. The question states that f=10cm and u=15cm, This can be substituted in the lens equation as follows: 1/15+1/v=1/10 1/v =1/30 V=+30 Magnification =v/u =30/15=2. The positive sign of v means the image is real, inverted and it on the opposite side of the object. Solution: The image is twice the same size as the object, real, inverted and on the opposite of the object.
S=vt-16t2 solve for v is what I will assume you mean. first pull out the t S=t(v-16t) then devide by t S/t=v-16t Then add 16t to both sides S/t + 16t = v This can also be written as (S+16t2)/t = v
If: v = u+at Then: -u = -v+at or u = v-at (by dividing all terms by -1) a = (v-u)/t t = (v-u)/a
T. V. Bulpin was born in 1918.
V. T. Bhattathiripad died in 1982.
V. T. Bhattathiripad was born in 1896.