Try adding a adding a capacitor.
Var is controlled by adding inductors or capacitors in parallel with loads requiring reactive power. By adding a capacitor of proper size in parallel with a inductive load results in the load drawing VAR from the capacitor instead of the source.
A: The ratio of emitter/collector resistance is the gain. by adding a capacitor on the emitter the AC parameters will shift as a function of frequency
I am going to assume that the capacitor in question has one uf or mfd rating and the one you want to use has two such as: 30+7.5uf if so then yet as long as you hook to the terminals that supply the same uf as the oem capacitor. The terminal marked HERM will be the terminal that has the highest of the two uf ratings. hope this helps!!
A: A TRANSISTOR gain is determined by current flow on the collector by adding a resistor to the emitter this current flow is reduced by adding or bypassing this resistor with a capacitor the net effect is that this emitter resistor will be reduced in value as frequency increases therefore change gain as a function of frequency input
That will depend on whether you are adding charge to it or taking charge away.
Simple technique by adding PP capacitor with automatic power factor controller.
by adding a capacitor on the start winding
Adding a capacitor bank makes absolutely no difference whatsoever to the amount of energy consumed (in kilowatt hours). The capacitor bank might reduce the load current, but this does not affect the amount of energy consumed. Anyone who tries to sell you a 'capacitor bank' in order to save you energy is selling a SCAM!
In order for a capacitor to pass current, the voltage across it must be changing. In a DC circuit, the voltage does not change so, at equilibrium, the capacitor is effectively an open circuit. We also call this DC blocking. You can take a signal with DC bias on it, perhaps because it came from a class A BJT amplifier, couple it with a capacitor, and the signal will make it through, but the DC bias will not.
Capacitors are used to improve an inductive load's power factor towards unity. The power factor before and after adding the capacitor bank depends entirely on the inductive/capacitive values involved.
is a device that smoothen your half-wave rectification into a full-wave rectification after using a 4 diode and 1 resistor , after adding a capacitor , there will be a almost steady output , it charges the capacitor when is forward biased which is the first half wave , and discharge when is reverse biased to stablelize the wave into a almost same potential difference compare to a.c