The orbital circumference of a planet is determined by both the mass and size of a planet. Although a planet will orbit the sum in an eliptical sphere shaped orbit, the circumference of these are almost always relative to the mass and density of the planet. It is also determined on how far away it is from the sun. The orbital circumference of a planet is determined by both the mass and size of a planet. Although a planet will orbit the sum in an eliptical sphere shaped orbit, the circumference of these are almost always relative to the mass and density of the planet. It is also determined on how far away it is from the sun.
Measure the diameter and from that calculate the volume, then determine the mass of the sphere on a weighing device. Then it's just density = mass/volume ========================== It again depends on the sphere whether its hollow or its a solid sphere
It stand for sphere shaped orbital which can house two electrons
0.723
Density is the mass per unit volume. e.g. kg/m3. But you've only given one of the quantities needed - we still need the volume of the sphere.
Assuming the ball is a perfect sphere of uniform density, and is suspended from a massless string, the centre of gravity is in the centre of the ball.
the 2s orbital is at a higher energy level
S
The orbital circumference of a planet is determined by both the mass and size of a planet. Although a planet will orbit the sum in an eliptical sphere shaped orbit, the circumference of these are almost always relative to the mass and density of the planet. It is also determined on how far away it is from the sun. The orbital circumference of a planet is determined by both the mass and size of a planet. Although a planet will orbit the sum in an eliptical sphere shaped orbit, the circumference of these are almost always relative to the mass and density of the planet. It is also determined on how far away it is from the sun.
a gold sphere
Coccus
The nuclear atom differs from the uniform sphere model, because they both are made from different atoms because of the elements.
It's an older term; nowadays the phrase "Center of mass" seems to be preferred. It's, basically, the mass-weighted center of a ... well, a thing. The center of a sphere of uniform density is easy to calculate; it's the geometric center of the sphere. For other shapes or for objects where the density is not the same throughout, it's more complicated.
The 1s is a sphere, crossing all axis of course. all the s orbitals are a sphere. p orbital are opposile nodes on the x, the y, and the z axis.
When you go down below the surface of the Earth, the gravity will initially INCREASE. This is because Earth's density is not uniform - there is more mass concentrated closer to the center, than in the case of a sphere of uniform density. If Earth were a sphere of uniform density, the gravity would get less, once you go below the surface - because some of Earth's material would pull you upward.In any case, if you go further down, eventually the force of gravity will become less. When the gravity increases (as it does initially), the period will become shorter.
how do you find the mass of a sphere Volume x density => 4/3(pi)(r)3 x density
Dalton