0
Example: XeO3
Hybridization=1/2[0+8+0]
=1/2(8)=4
So Hybridization is SP3.
Another Example:- XeF6
Hybridization=1/2(8+6+0)
=1/2(14)=7
So Hybridization of XeF6 sp3d3
We can try take all examples find the Hybridization that componds.
there's one easy method too... Its sigma + lone pairs..............In XeO3, There are 3 sigma bonds and one lone pair... Therefore hybridisation is 4. its sp3.... Similarly its for XeF6....
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