In the laboratory, copper(I) Iodide is prepared by simply mixing an aqueous solutions of potassium iodide and a soluble copper(II) salt such copper sulphate. : :: Cu2+ + 2I− → CuI2 The CuI2 immediately decomposes to iodine and insoluble copper(I) iodide, releasing I2. : :: 2 CuI2 → 2 CuI + I2
copper iodide
No, it is not soluble in water
2K(I) + CuCl2 => 2KCl + Cu(I)2 The (I) is iodide, because the capital I and lowercase l look the same. This is a double replacement reaction, where copper (II) iodide comes out of solution, because it's not soluble, assuming that both of those are in solution.
Copper iodide is an ionic compound.
No. Copper iodide is insoluble in water.
In the laboratory, copper(I) Iodide is prepared by simply mixing an aqueous solutions of potassium iodide and a soluble copper(II) salt such copper sulphate. : :: Cu2+ + 2I− → CuI2 The CuI2 immediately decomposes to iodine and insoluble copper(I) iodide, releasing I2. : :: 2 CuI2 → 2 CuI + I2
Yes. Barium Iodide is soluble in water.
copper iodide
No, it is not soluble in water
2K(I) + CuCl2 => 2KCl + Cu(I)2 The (I) is iodide, because the capital I and lowercase l look the same. This is a double replacement reaction, where copper (II) iodide comes out of solution, because it's not soluble, assuming that both of those are in solution.
Copper iodide is an ionic compound.
It is false; sodium iodide is more soluble than sodium chloride in water.
Ethyl iodide is miscible with ethanol.
Yes, it is
How to remove iodine from a solution of water? I'm assuming your talking about a iodine salt (such as sodium iodide) as elemental iodine (I2) is not that soluble in water. To remove simply add in another salt (such as copper sulfate) that will react with the iodide producing an insoluble salt (copper iodide) which can then be removed.
Magnesium iodide is soluble in ethanol, ammonia or ethyl ether.