Yes, yes, go on. What is your question ?
Yes. That's what "uniform electric field" means.
due electrostatic force
an electric charge seas up an electric field in it's surroundings.it exerts force upon any charges which arrives in this field region.the force will be stronger when the field intensity is higher
The electric field, in this case, would be the same, no matter how far you go from the plate.
Electric field intensity is related to electric potential by the equation E = -dV/dx, where E is the electric field intensity, V is the electric potential, and x is the distance in the direction of the field. Essentially, the electric field points in the direction of decreasing potential, and the magnitude of the field is related to the rate at which the potential changes.
Electric flux.
Yes, it is.
Yes, yes, go on. What is your question ?
Yes. That's what "uniform electric field" means.
due electrostatic force
Position, velocity, acceleration, force, momentum, electric field, magnetic field.
Component vectors can be used with a variety of different used in physics, including displacement, force, acceleration, electric field, etc.
No,because electric field (force/charge) is a vector quantity, i.e. , it has both magnitude as well as direction.
Both. The electric field is a Quaternion field, a scalar e and a vector E, E = [e,E]Maxwell's Equation. 0=XE= [d/dr, Del][e,E] = [de/dr -Del.E, dE/dr + Del e] = [db/dt - Del.E, dB/dt + Del e]
Component vectors can be used with a variety of different used in physics, including displacement, force, acceleration, electric field, etc.
an electric charge seas up an electric field in it's surroundings.it exerts force upon any charges which arrives in this field region.the force will be stronger when the field intensity is higher