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The strength of the electric field is a scalar quantity. But it's the magnitude of thecomplete electric field vector.At any point in space, the electric field vector is the strength of the force, and thedirection in which it points, that would be felt by a tiny positive charge located there.
Scalar
no electric field is not a potential field .ELECTRIC FIELD IS A SCALAR QUANTITY WHERE AS POTENTIAL IS THE VECTOR QUANTITY. NO SCALAR QUANTITY HAS A FIELD SO THERE IS NO RELATION BETWEEN ELECTRIC FIELD AND POTENTIAL OR IN OTHER WORD POTENTIAL HAS NO FIELD <<>> An electric field is a vector field, because it has magnitude and direction. A pair of charged parallel plates has an electric field between them directed from the negative to the positive plate. The electric field is the gradient of the potential, which is another field but a scalar one. A field is just a quantity with a value that depends on positon. The potential is measured in volts and if one plate is grounded and the other at positive potential V, the potential rises from zero to V as the position changes from the lower plate to the top one.
I think light could not be recoginzed as a vector. However, I think the light intensity could be devided into the x-y axises.
A quantity that has both magnitude and direction often has an arrow drawn over the unit of measurement. This is known as a vector quantity, as opposed to a scalar quantity which has no direction.
No,because electric field (force/charge) is a vector quantity, i.e. , it has both magnitude as well as direction.
The strength of the electric field is a scalar quantity. But it's the magnitude of thecomplete electric field vector.At any point in space, the electric field vector is the strength of the force, and thedirection in which it points, that would be felt by a tiny positive charge located there.
The strength of the electric field is a scalar quantity. But it's the magnitude of thecomplete electric field vector.At any point in space, the electric field vector is the strength of the force, and thedirection in which it points, that would be felt by a tiny positive charge located there.
Scalar
Vector.
no electric field is not a potential field .ELECTRIC FIELD IS A SCALAR QUANTITY WHERE AS POTENTIAL IS THE VECTOR QUANTITY. NO SCALAR QUANTITY HAS A FIELD SO THERE IS NO RELATION BETWEEN ELECTRIC FIELD AND POTENTIAL OR IN OTHER WORD POTENTIAL HAS NO FIELD <<>> An electric field is a vector field, because it has magnitude and direction. A pair of charged parallel plates has an electric field between them directed from the negative to the positive plate. The electric field is the gradient of the potential, which is another field but a scalar one. A field is just a quantity with a value that depends on positon. The potential is measured in volts and if one plate is grounded and the other at positive potential V, the potential rises from zero to V as the position changes from the lower plate to the top one.
Both. The electric field is a Quaternion field, a scalar e and a vector E, E = [e,E]Maxwell's Equation. 0=XE= [d/dr, Del][e,E] = [de/dr -Del.E, dE/dr + Del e] = [db/dt - Del.E, dB/dt + Del e]
A magnetic field is neither: it is a vector field with both direction and quantity.
Money is a scalar quantity because it can be used in any field[no particular direction]
Scaler. Its vector counterpart is the electric field.
For a physical quantity to be termed a vector quantity, having magnitude and direction is not enough. The quantity should obey the laws of vector addition too. Like the triangle law or the parallelogram law. As we know, if two currents meet at a junction, the total current of the resultant current will be the algebraic sum of the two current and not the vector sum.Sometimes, treating a current like a vector makes sense, like when the current though a conductor induces a magnetic field.
I think light could not be recoginzed as a vector. However, I think the light intensity could be devided into the x-y axises.