Balanced equation first. 2H2 + O2 >> 2H2O 1.42 mol H2 ( 1mol O2/2mol H2 ) = 0.71mol O2 to react with H2
H2 and O2.
First off, you decide the product (becomes easier after a while of doing chemistry). The product is H2O (water). O2+H2=>H2O, but this is not stochiometrically balanced, so you have to change the amount of H2O's on the right side of equation and then to balance the amount of hydrogens. If you add a 2 in front of both, you get O2 + 2H2 => 2H2O
Balanced equation. 2H2 + O2 -> 2H2O 355 grams O2/32 grams = 11.1 moles O2 check for limiting reactant 11.1 moles O2 (2 mole H2/1 mole O2) = 22.2 mole H2 and H2 has no where near that many moles, so limits and drives reaction so, as they are one to one...... 22.2 moles of H2O are produced
Oxygen limits the reaction, so......Balanced equation. 2H2 + O2 -> 2H2O 7.89 mole H2O (1 mole O2/2 mole H2O) = 3.95 mole oxygen gas needed ------------------------------------------
No. It would have to be H2O2 - H2 = O2 in order to be balanced.
It is not balanced. There should be a 2 in front of H2 and H2O
Balanced equation first. 2H2 + O2 >> 2H2O 1.42 mol H2 ( 1mol O2/2mol H2 ) = 0.71mol O2 to react with H2
2 H2 + O2 = 2 H2O
= H2+O2 =2H2+O2=2H2O
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
Because there are 2 oxygen atoms on the reactants side and only one on the products side. You can either add a coefficient of 1/2 on the O2 or you can add a coefficient of 2 on H2 and H2O.
Water decomposes into Oxygen and Hydrogen gases, each of which is a 2 atom molecule: H20 -> H2 + O2 BUT that's not balanced - there's Oxygen 'appearing' from nowhere on the right side so to balance it (2) H2O -> H2 + O2 But now we have 4 Hydrogens on left and only two on right (2) H2O -> (2)H2 + O2 4 hydrogens and 2 oxygen - > 4 hydrogens and 2 Oxygens Balanced!
H2 and O2.
H2 (Hydrogen) reacts with O2 (Oxygen) to form water. 2 H2 + O2 --> 2 H2O
Balanced equation: 2 H2 + O2 --> 2 H2O
2h2o -> 2h2 + o2