No. Hydrogen atoms combining to form helium is nuclear fusion. Alpha decay is a process whereby a large atomic nucleus ejects a helium nucleus.
Alpha decay is a process where an atom emits an alpha particle, which is a helium nucleus consisting of 2 protons and 2 neutrons. Since a hydrogen atom only has one proton, it cannot undergo alpha decay as it lacks the necessary particle combination to release an alpha particle.
daughter element
Alpha decay. Alpha particles are the same as a helium-4 nucleus.
These are all phenomenons in nuclear physics.
No, alpha decay does not directly produce helium atoms. Alpha decay is a type of radioactive decay in which an atomic nucleus emits an alpha particle, which consists of two protons and two neutrons. This alpha particle is the same as a helium-4 nucleus, but it is not considered a helium atom until it captures electrons and becomes electrically neutral.
The possible products of the alpha decay of uranium-238 are thorium-234 and helium-4. During alpha decay, the uranium nucleus releases an alpha particle (helium nucleus) and transforms into thorium-234.
A helium nucleus - more precisely, a helium-4 nucleus - is called an alpha particle. The corresponding decay would be called alpha decay.
Helium and hydrogen do not emit alpha particles because they contain only one or two protons in their nuclei respectively, which is insufficient for them to emit an alpha particle consisting of two protons and two neutrons. Alpha decay typically occurs in heavier elements with larger atomic numbers where the nucleus is unstable and emits an alpha particle to reach a more stable configuration.
Alpha nuclear decay
Lead-210 decays by alpha or beta decay. The equation for the alpha decay of 210Pb is: 82210Pb --> 80206Hg + 24He representing the alpha particle as a helium nucleus. The equation for the beta decay of 210Pb is: 82210Pb --> 83210Bi + -10e where the -10e is an electron.
Alpha decay is the loss form the atomic nucleus of an "alpha" particle - that is 2 protons and 2 neutrons (a helium nucleus).
The equation for the alpha decay of 222Rn is: 86222Rn --> 84218Po + 24He Where He represents the alpha particle, which can also be viewed as a Helium nucleus.