The chat room phenomenon is complicated in that it seeks to establish a social forum without any context for behavior or personal safety. As well, usually people engage in chat rooms when alone or isolated, which is not the best circumstance. One should always protect one's personal information. Most people use "handles" in chat rooms, or nick names by which they want to be identified. This is not a sin, in fact, if one must engage in chat rooms it is recommended to use a handle in order to ensure that your personal information is safe from those who might use it to either exploit or harm you. If someone flat out asks you for personal information you can simply say you do not wish to advance it. It is probably best to avoid chat rooms as a rule because of their threat and instead spend time doing other more hands on social activities with friends and family and your community at large. Chatting with people you know in real life is best.
False
The identity for tan(theta) is sin(theta)/cos(theta).
Sine sum identity: sin (x + y) = (sin x)(cos y) + (cos x)(sin y)Sine difference identity: sin (x - y) = (sin x)(cos y) - (cos x)(sin y)Cosine sum identity: cos (x + y) = (cos x)(cos y) - (sin x)(sin y)Cosine difference identity: cos (x - y) = (cos x)(cos y) + (sin x)(sin y)Tangent sum identity: tan (x + y) = [(tan x) + (tan y)]/[1 - (tan x)(tan y)]Tangent difference identity: tan (x - y) = [(tan x) - (tan y)]/[1 + (tan x)(tan y)]
cos(x) = sin(pi/2 + x)
sec x - cos x = (sin x)(tan x) 1/cos x - cos x = Cofunction Identity, sec x = 1/cos x. (1-cos^2 x)/cos x = Subtract the fractions. (sin^2 x)/cos x = Pythagorean Identity, 1-cos^2 x = sin^2 x. sin x (sin x)/(cos x) = Factor out sin x. (sin x)(tan x) = (sin x)(tan x) Cofunction Identity, (sin x)/(cos x) = tan x.
An identity is a statement which says two quantities are equal, like as x + y = y + x or sin (x + y ) = sin x cos y + cos x sin y .
Trig identity... sin/cos = tangent
It is unclear what the questioner is looking for. Chats in Java may refer to web forums which are dedicated to those users interested in Java. No clear translation for 'chat sin java' has been found.
To show that (cos tan = sin) ??? Remember that tan = (sin/cos) When you substitute it for tan, cos tan = cos (sin/cos) = sin QED
I suggest that it is (sin A)^2 + (cos A)^2 = 1
YES!!!! Sin(2x) = Sin(x+x') Sin(x+x') = SinxCosx' + CosxSinx' I have put a 'dash' on an 'x' only to show its position in the identity. Both x & x' carry the same value. Hence SinxCosx' + CosxSinx' = Sinx Cos x + Sinx'Cosx => 2SinxCosx
Yes Jesus saves us from sin and death