answersLogoWhite

0


Best Answer

No, it is not possible for a diverging or a concave lens to form a real image. It always forms virtual and erect image

User Avatar

Wiki User

13y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Is it possible for a diverging lens to form a real image Explain?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Physics

What are virtual and real images and what is the difference between them?

Here we have to note down an interesting point. If we have a source of light, then the rays starting right from the source would be diverging definitely. Hence if the rays coming from a source is of diverging type then the source is a real one. If otherwise the rays assumed coming from a source is converging type then we can declare that the source would be a virtual one. Same manner to form an image on a screen the rays have to converge. So converging rays would give definitely a real image. If the rays which are destined to give an image are of diverging type then the image must be termed as virtual. To get the position of the virtual image we have to extend back the rays so as they meet at a point and we say that the rays appear to diverge from that point hence named as virtual image. Thus we generalize this way. In case of source if rays are of diverging then source is real, if converging then source is virtual. In case of image formation, if rays are converging then real image and if diverging then virtual image. This is the cute point to be realized and to be taught to the students of this generation.


Why it is impossible to form real images with plane mirrors?

A real image is formed when light rays coming from a point* after reflection meet at a point. Light rays coming from a point are always diverging, so after reflection by a plane mirror also they remain diverging and never meet. We need to use an optical device that can converge the rays to get a real image. * Its strictly a point not an extended object.


How can you tell whether a convex lens will produce a real or virtual image?

The secret is that after refraction through convex lens if the refracted rays converge then it would form a REAL image and if the rays are diverging then it would form a VIRTUALimage.So, when the object is at or beyond the focus (F) of the convex lens then we have only converging refracted rays, hence real imageIf the object lies in between focus (F) and optical centre (O) of the lens, then refracted rays come out diverging and so only virtual images are formed.


What kind of images does a convex lens produce?

Convex lenses form real images and concave lenses form virtual images. But there is one case in which convex lens also forms virtual images. This is when object is placed between Principal Focus "F" and Optical Centre "O"


Describe the image form mirror by a plane mirror?

image form can be form by virtual image

Related questions

The function of the lens is to?

The function of lens is to to form an image of an object by converging or diverging rays of light from the object.


Why real image don't form in plane mirror?

When diverging rays from a point source fall on the plane mirror, after reflection would once again diverge and never get a chance of converging. So any diverging rays cannot form a real image and they are considered to be coming from one point and that point is taken to be the virtual image.


What does diverging boundaries form?

is a boundary


An object is located 51mm from a diverging lens the object has a height of 13mm and the image height is 3.5mm?

An object is located 51mm from a diverging lens the object has a height of 13mm and the image height is 3.5mm?Diverging lens do not form real images.When parallel rays of light passes thru a diverging lens, the rays diverge (spread apart) on the other side of the lens. It forms a virtual image. The object will look smaller.The image is on the same side of the lens as the object, so f is negative.Do = 51mm Ho = 13mmDi = ______ Hi = 3.5mmDi = -13.7mm1/Di + 1/Do = 1/f1/-13.5 + 1/51 = 1/ff = -18.36 mm


Why do you get a virtual image?

In case of a concave lens the only possibility is that when parallel rays make an entry then they have to diverge. NO diverging rays can form a real image on a screen as they could not meet at a point. If the already diverging rays make an entry then they get diverged further and so no chance of getting real image. Hence the diverging rays appear to originate from a point on the same side of the object and so a virtual image. In case of a convex lens if the object is placed in between the optic centre and the focal plane then the refracting rays have to diverge and so virtual image. This is what a palmist does as he uses to see the lines on the palm to foretell the future.


What are virtual and real images and what is the difference between them?

Here we have to note down an interesting point. If we have a source of light, then the rays starting right from the source would be diverging definitely. Hence if the rays coming from a source is of diverging type then the source is a real one. If otherwise the rays assumed coming from a source is converging type then we can declare that the source would be a virtual one. Same manner to form an image on a screen the rays have to converge. So converging rays would give definitely a real image. If the rays which are destined to give an image are of diverging type then the image must be termed as virtual. To get the position of the virtual image we have to extend back the rays so as they meet at a point and we say that the rays appear to diverge from that point hence named as virtual image. Thus we generalize this way. In case of source if rays are of diverging then source is real, if converging then source is virtual. In case of image formation, if rays are converging then real image and if diverging then virtual image. This is the cute point to be realized and to be taught to the students of this generation.


What feature forms at diverging oceanic plates?

Ridges of buoyant oceanic crust form at diverging oceanic plate boundaries.


Can a concave lens form a real image?

Never. Since the rays coming from a real object will always be diverging. The action of a concave lens is diverging action. Hence the already diverged rays will be dirverged further. Hence no chance of convergence. Only converging rays would form a real image. Hence the answer, NEVER.


Why it is impossible to form real images with plane mirrors?

A real image is formed when light rays coming from a point* after reflection meet at a point. Light rays coming from a point are always diverging, so after reflection by a plane mirror also they remain diverging and never meet. We need to use an optical device that can converge the rays to get a real image. * Its strictly a point not an extended object.


Do volcanoes that form at mid-ocean ridgeoccur at a diverging plate boundary?

A mid ocean ridge is a diverging plate boundary so the simple answer is yes.


Does new crust form at diverging tectonic plate?

Yes, of course.


Why might diverging plates cause a volcano to form?

Diverging plates are associated with stretching and thinning of the crust. Lines of weakness or rifts in the thinner crust serve as conduits for magma and volcanoes often form.