No light is the fastest possible. Nothing escapes the velocity of light.
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Sure. The escape velocity at some appropriate distance from a black hole is
equal to 'c'. That's why the hole is black. The exact value of the distance
depends on the hole's mass.
The escape velocity of a black hole is equal or greater than the speed of light, so light cannot escape
The word "black" aptly describes the inability of light to escape - all light and matter that passes the event horizon can only do so in one direction, falling in. The reason is, the escape velocity inside the event horizon is greater than the speed of light, the event horizon itself being the boundary at which the escape velocity is equal to that speed. Outside that horizon, the escape velocity is less than the speed of light, hence it would be possible for light and objects moving at speeds approaching that of light to escape.
For two bodies with equal radius, the more massive has the greater escape velocity. For two bodies with equal mass, the one with smaller radius has the greater escape velocity. Both conditions listed in the question indicate greaterescape velocity.
Yes, yes it is
Escape velocity is the velocity that an object needs in order to reach infinite distance, wherein the force will equal to zero. Orbital velocity is the velocity of an object so it can stay in orbit.
the rocket speed required to escape out of the earth's gravity is known as escape velocity which is numerically equal to 11.2 km per sec.
The escape velocity equation is derived by setting the kinetic energy of an object equal to the gravitational potential energy at the surface of a planet. By equating these two energies, we can solve for the velocity needed for an object to escape the planet's gravitational pull. The equation is derived using principles of energy conservation and Newton's laws of motion.
In order for a body to escape the gravitational pull of the Earth, it needs to be thrown up with an initial velocity equal to or greater than the escape velocity of around 11.2 km/s. This velocity allows the object to overcome the gravitational pull of the Earth and continue traveling away from it indefinitely.
It is called the Schwarzschild radius
if it was a continuous velocity then 10mps i guess because that is the terminal velocity when an object is dropped this is another person who answer actuallyn you are wrong terminal velocity is the maximum
The body will be striking the Earth with a velocity equal to its escape velocity, which is around 11.2 km/s. At this velocity, the body will have enough kinetic energy to overcome the gravitational pull of the Earth and reach the surface.
When something increases in velocity, its momentum would increase because momentum is equal to its mass * velocity. This means that the momentum and velocity are proportional, so twice the velocity is twice the momentum, and so on.