Yes, but it would be very long and narrow. To get a perimeter of 30 you could have two sides that are 14 and two sides that are 1 which gives an area of 14. Conversely you could have an object with two sides that are 13 and two sides that are 2 which gives you an area of 26. Since 18 is between 14 and 26, there must be a shape between these two shapes that has area 18 and perimeter 30. You can find out exactly what those dimensions are by solving the two simultaneous equations for area and perimeter.
area = width X height
and
perimeter = 2width + 2height
knowing the area and perimeter, solve one equation for width or height and plug it into the other equation and solve.
It can be 56.25 or anything less, but not more. You can't tell the area from the perimeter, and you can't tell the perimeter from the area. -- if each side is 7.5, the perimeter is 30, and the area is 56.25 -- if it's (5 by 10), the perimeter is still 30, and the area is 50 -- if it's (4 by 11), the perimeter is still 30, and the area is 44 -- if it's (3 by 12), the perimeter is still 30, and the area is 36 -- if it's (2 by 13), the perimeter is still 30, and the area is 26 -- if it's (1 by 14), the perimeter is still 30, and the area is 14
If we restrict ourselves to whole numbers, then 1 x 14 will have the least possible area.
b and h both equal 30 (square); area = 30 X 30 = 900 SQ IN
18" is not a possible perimeter measurement. Assume the dimensions of the rectangle are so close to those of a square that the difference can be disregarded. This is the condition when the perimeter is at its minimum. When the rectangle measures approximately 6" x 6", its area = 36 sq ins, its perimeter = 24" For the area to remain constant then as the length increases by a factor n the width must decrease by that same factor. Area = 6n x 6/n : perimeter = 12n + 12/n :so when n = 1, Perimeter = 12 + 12 = 24 As n increases, say n = 2, Perimeter = 24 + 6 = 30 : And the perimeter continues to increase as the rectangle becomes narrower. Eventually, it will become so narrow that for diagram purposes it will appear as a straight line.
There is no such shape. Firstly, because no shape can jave an area of 100 cm. Suppose, though, that its area were 100 SQUARE cms, even then, there is no possible solution. Of all the shapes possible with a given perimeter, a circle has the greatest area. A perimeter of 30 cm means a radius of 30/(2*pi) = 15/pi cm. A circle with this radius would have an area of pi*(15/pi)2 = 225/pi = 71.62 sq cm : well below the area required.
14 cm^3 (14+14+1+1=30 and 14*1=14cm^3)
The area doesn't tell you the dimensions or the perimeter. It doesn't even tell you the shape. -- Your area of 36 cm2 could be a circle with a diameter of 6.77 . (Perimeter = 21.27.) -- It could be a square with sides of 6 . (Perimeter = 24.) -- It could be rectangles that measure 1 by 36 (Perimeter = 74) 2 by 18 (Perimeter = 40) 3 by 12 (Perimeter = 30) 4 by 9 (Perimeter = 26). There are an infinite number of more rectangles that it could be, all with the same area but different perimeters.
There is no such thing as the area of the perimeter. A perimeter is a length and so has only 1 dimension. As such, its area is 0.
56.25m2
Area: 54 square cm Perimeter: 30 cm
An area cannot be 30m since that is a linear measure, not the measure of an area. The lowest perimeter, for an area is attained by a circle. So for an area of 30 m2 this was attained by a circle of radius R, then πR2 = 30 so that R2 = 30/π and R = sqrt(30/π) The perimeter = 2*π*R = 2*π*sqrt(30/π) = 2*sqrt(30*π) = 19.42 metres
900