Want this question answered?
False
No. Average velocity is still a velocity.Distance is a product of (a velocity or speed) times (a length of time).
Velocity is NOT the slope of the acceleration vs. time graph. Velocity is the area under the acceleration vs. time graph. Velocity is the slope of a position vs. time graph, though. For you Calculus Junkies, v = the integral of acceleration with respect to time.
C. one of the above.
False. The slope of a velocity vs time graph is acceleration
False
No. Average velocity is still a velocity.Distance is a product of (a velocity or speed) times (a length of time).
Velocity is NOT the slope of the acceleration vs. time graph. Velocity is the area under the acceleration vs. time graph. Velocity is the slope of a position vs. time graph, though. For you Calculus Junkies, v = the integral of acceleration with respect to time.
C. one of the above.
FALSE!
Ahorizontal line on a velocity vs time graph does not indicate any acceleration because there is no slope. Speed remains constant.
False
Is this a question? or a statement that you are unsure of? Well anyways, this would be correct if acceleration was a constant but if acceleration is not a constant, the (not-constant) acceleration would change the rate of velocity and thus that statement/question would be false.
The answer is FALSE- acceleration would be correct
False. The slope of a velocity vs time graph is acceleration
False. It has negative acceleration.
Yes as a body moves along a circular path with uniform speed, its direction is ever changing. Hence the velocity is changing. So acceleration must be present. If acceleration vector is in the direction of the velocity then definitely its magnitude would change and so we cannot say the motion to be uniform. So the acceleration has to be perpendicular to the velocity vector, so it has to be along the radius. Hence the acceleration is named as radial acceleration. The force thus produced is known as centripetal force ie centre seeking force.