Q1: A PN juncrion has to be reverse-biased for a transiton capacitance to exist. In forward bias there is no depletion layer and the junction conducts, so it does not behave as a capacitance.
Q2: In a common-emitter circuit the ouput voltage appears across a resistor connected between the collector and the positive rail (for a normal NPN transistor). Therefore when the current through the transistor increases, there is more voltage drop across this resistor and the collector voltage has to fall.
you have it reversed. capacitance increases with decrease in distance of plates.
To decrease the resonant frequency of any tuned circuit, increase the inductance and/or increase the capacitance.
A: the capacitance will increase. in series it will decrease accordingly CPARALLEL = Summation1-N (CN) CSERIES = 1 / Summation1-N (1 / CN)
capacitance also increase
Capacitance increases with a decrease in distance between plates because the electric field between the plates becomes stronger, storing more electric charge per unit voltage. This results in a higher capacitance value since the plates can hold more charge for the same applied voltage.
(a) Charge Will increase (b) Potential difference will stay the same (c) Capacitance will increase (d) Stored energy will decrease
Not much if it is a fixed capaitor. If it is a variable capacitor, rotating the shaft to mesh the two sets of plates more closely will increase the capacitance.
An increase in temperature typically causes matter to change from a solid to a liquid or from a liquid to a gas. A decrease in temperature often results in the opposite transition, causing matter to change from a gas to a liquid or from a liquid to a solid.
any capacitance is given by equation C = (epsilon * A/ d) where d is distance between two plates, thus as d reduces C increases. Now, in depletion region as we increase reverse bias, the depletion region width increases. Now consider depletion region as a parallel plate capacitor, with positive charges on n side and negative charges on p side. Thus, as reverse bias increases, d of junction capacitance increases thus capacitance reduces. On other hand, as reverse bias reduces, d of junction capacitance reduces, thus capacitance increases. -Amey Churi
increase the capacitance of the capacitor by a factor of two. This is because capacitance is directly proportional to the area of the plates.
no. :)
The midpoint between decrease and increase is stability or equilibrium, where there is neither a decrease nor an increase occurring.