Yes. If you reduce the voltage to the same device, then it uses less power.
True power is expressed in watts, so the true power of your heater is its kilowatt rating at its rated voltage. Variations in voltage will result in variations in its power. Assuming its resistance remains roughly constant for variations in temperature, then True Power = V2/R.
well you can make it in less than a 1000 watts but it would take forever!
The equation to use to find wattage is W = A x V. Watts are equal to the amperage times the voltage. Look on the nameplate of the unit to find the true amperage and voltage needed to operate the refrigerator.
Think about an electric light bulb connected to power through a dimmer. As you reduce the voltage the bulb gets dimmer and provides less wattage and less light. That is less work is being done. Hence power is reduced.Where did the voltage go?If the bulb is 60W, R=1202/60=240 ohmsand you add say a 100 ohm maximum resistive dimmer,your total resistance for the circuit is now 340 ohmsyour current is 120 V / 340 ohms = .3529 ampsvoltage drop across the dimmer is .3529 amps x 100 ohms = 35.29 volts120 - 35.29 = 84.71 volts left for the light84.71 V x .3529 amps = 29.89 watts consumed by the light29.89 watts is < 60 watts more than 50% savings!?35.29 V x .3529 amps = 12.454 watts consumed by the dimmer29.89 W + 12.454 W = 42.344 watts total consumed in this circuit42.344 watts is still less than 60 watts by 17.656 watts, butYou have less than 50% light output and still consume more than 70% of the original power! Not very efficient.AnswerFirst of all, appliances do not consume power; they consume energy. Power merely indicates the rate at which energy is consumed. Secondly, assuming the appliance's resistance remains constant (not necessarily the case) power is proportional to the square of the voltage. So, reducing the voltage will significanly reduce the power of the appliance.
power factor is the cosine of the angular difference between current and voltage and must be taken into account to get true power (watts)
true
It depends on the voltage of the compressor. Two horse power (electric) is 1492 watts, but watts are volts times amps, so you need to know the voltage. Since the motor is an inductive load, you will also need to know the power factor, so as to compensate for true vs apparent power.
No, the opposite is true. It is less light during the winter.
true, it can be measured in kilowatts too.
Its 'true power', expressed in watts, will be zero, while its 'reactive power', expressed in reactive volt amperes, will be the product of the voltage across the inductor and the current through it.
true A+
true A+