If space were entirely empty this would be true, but even minute gravitational forces can change the trajectory and velocity of a projectile.
horizontal
the horizontal component remain unchanged because there in no acceleration in horizontal direction
In projectile motion, since , there's no force in the horizontal direction which can change the horizontal motion therefore the horizotal velocity remains conserved Vx=Vox= Vocos theta by using above formula , constant horizontal initial or final velocity can be found. since Initial = final horizontal velocity.
The vertical velocity is 0. The horizontal velocity is constant during the entire trajectory (and may be zero).
Since the velocity is constant due to the fact that there are no external forces acting in the horizontal direction, if you neglect air resistance, therefore, the horizontal velocity of a projectile is constant.
horizontal
the horizontal component remain unchanged because there in no acceleration in horizontal direction
In projectile motion, since , there's no force in the horizontal direction which can change the horizontal motion therefore the horizotal velocity remains conserved Vx=Vox= Vocos theta by using above formula , constant horizontal initial or final velocity can be found. since Initial = final horizontal velocity.
The vertical velocity is 0. The horizontal velocity is constant during the entire trajectory (and may be zero).
The horizontal distance will be doubled.
Since the velocity is constant due to the fact that there are no external forces acting in the horizontal direction, if you neglect air resistance, therefore, the horizontal velocity of a projectile is constant.
rainbow trajectory
That combination is called "projectile motion". In the absence of air resistance, its shape is always a parabola.
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
A projectile that is thrown with an initial velocity,that has a horizontal component of 4 m/s, its horizontal speed after 3s will still be 4m/s.
A projectile will travel on a straight line unless external forces act upon it. Gravity will pull the projectile downward, i.e. affect its vertical velocity component. This is why the projectile will decelerate upwards, reach a maximum elevation, and accelerate back down to earth. The force vector of air resistance points in the opposite direction of motion, slowing the projectile down. For example, If the projectile is going forward and up, air resistance is pushing it backwards (horizontal component) and down (vertical component). Without air resistance, there is no external force acting upon the horizontal velocity component and the projectiles ground speed will stay constant as it gains altitude and falls back down to earth.