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The horizontal component of velocity for a projectile is not affected by the vertical component at all. Horizontal component is measured as xcos(theta) Vertical component is measured as xsin(theta) Whereas theta is the angle, and x is the magnitude, or initial speed.
A projectile that is thrown with an initial velocity,that has a horizontal component of 4 m/s, its horizontal speed after 3s will still be 4m/s.
If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.
The initial velocity is sqrt(5) times the vertical component, and its angle relative to the horizontal direction, is 0.46 radians (26.6 degrees).
If it's fired horizontally, then its initial vertical velocity is zero. After that, the vertical velocityincreases by 9.8 meters per second every second, directed downward, and the projectile hitsthe ground after roughly 3.8 seconds.Exactly the same vertical motion as if it were dropped from the gun muzzle, with no horizontal velocity.
The horizontal component of velocity for a projectile is not affected by the vertical component at all. Horizontal component is measured as xcos(theta) Vertical component is measured as xsin(theta) Whereas theta is the angle, and x is the magnitude, or initial speed.
A projectile that is thrown with an initial velocity,that has a horizontal component of 4 m/s, its horizontal speed after 3s will still be 4m/s.
If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.
If the initial velocity is v, at an angle x to the horizontal, then the vertical component is v*sin(x) and the horizontal component is v*cos(x).
The initial velocity is sqrt(5) times the vertical component, and its angle relative to the horizontal direction, is 0.46 radians (26.6 degrees).
In the usual simple treatment of projectile motion, the horizontal component of the projectile's velocity is assumed to be constant, and is equal to the magnitude of the initial (launch) velocity multiplied by the cosine of the elevation angle at the time of launch.
If it's fired horizontally, then its initial vertical velocity is zero. After that, the vertical velocityincreases by 9.8 meters per second every second, directed downward, and the projectile hitsthe ground after roughly 3.8 seconds.Exactly the same vertical motion as if it were dropped from the gun muzzle, with no horizontal velocity.
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
The effect that gravity has on the vertical component of the projectile is that as the projectile is going upward it is decreasing 10m/s ever second it is going upward until it reaches its peak. at its peak its vertical component is zero. Then as it is going back to earth it is increasing at 10 m/s every second that is it going downward. for example, a boy throws a ball at 20 m/s upward its velocity after 2 seconds will be zero due to the fact that gravity canceled out the force and then.. what is the velocity after 4 seconds? it is 20 m/s.. gravity added 10 m/s ever second that it was falling to the earth. hope this helps
All that I can think of are: 1.) Gravity 2.) Wind 2.A) wind speed 2.B) direction of wind 3.) Angle of trajectory 4.) Initial speed of projectile 5.) Material through which projectile travels (as in density) 6.) Mass of projectile 7.) Spin 7.A) speed of spin 7.B) axis/axes spining occurs on 8.) Shape of projectile 9.) Temperature of medium projectile is in 10.) Size of projectile (as in height, width, and depth) 11.) Weighting of projectile 12.) Obsturctions to projectile's path In a vaccuum, though, these are the variables: 1.) Speed of object 2.) Obstructions in path 3.) Gravity
A projectile has an initial forward velocity.
A projectile has an initial forward velocity.