Ohm's Law doesn't apply to an incandescent lamp, regardless of its power rating. This is because the filament is manufactured from tungsten which is a 'non-ohmic' or 'non-linear' conductor, which means that the ratio of voltage to current changes for variations in voltage. For Ohm's Law to apply, this ratio must remain constant for variations in voltage.
Yes, Ohms law is applicable in altering current.
voltage! measured in volts. current X resistance = voltage simple ohms law
Temperature. Ohms law is applicable to measure resistance of an element at constant temperature only.
ohms law.
The voltage of a circuit with a resistance of 250 ohms and a current of 0.95 amps is 237.5 volts. Ohms's law: Voltage = Current times Resistance
Yes, Ohms law is applicable in altering current.
because they have a proportional relation
voltage! measured in volts. current X resistance = voltage simple ohms law
James Watt did not invent the light bulb. Thomas Edison is regarded by most people to have invented it. There were other similar ideas to the light bulb before Edison, however, it was his superior design and set up of entire electrical lighting systems that brought fame and popularity to his bulb. James Watt, is responsible for giving us the unit of measuring power that is his name (watt). The unit is derived by extending on Ohms law, to include that Voltage (e) times Amperage (i) = power.
In a typical residential 60 Watt incandescent bulb, the resistance of the filament is what dictates the current flow given a household voltage of 120 VAC the current is 1/2 amp. By Ohm's Law that means the resistance is 240 Ohms. In your example, a 60 Watt bulb at 30 Volts drawing 2 Amps would have a resistance of 15 Ohms. If you change the voltage to 15 Volts the resistance will still be 15 Ohms and current will be V/R = 1 Amp. The bulb, if it lit at all would be less than 1/2 as bright as the 30 Volt situation.
Temperature. Ohms law is applicable to measure resistance of an element at constant temperature only.
Generally the reason is because of too much heat from the incandescent bulb. Other reasons would be the amperage would exceed the wiring or the lamp socket. Using ohms law (power or watts = amperage times voltage), a 150 watt lamp would take 1.25 amps. A 120 watt bulb would take 1.0 amps. Probably in your question the engineer was concerned with heat instead of amps.
To find the resistance in ohms of a 194 12-volt bulb, you can use Ohm's Law (R = V/I). The 194 bulb typically has a current rating of about 0.25 amps. Using this information, the resistance would be approximately 48 ohms (R = 12V / 0.25A).
No, the wattage is determined by the resistance of the filament in the light bulb. The formula to determine the wattage is Watts = Voltage (squared)/Resistance in Ohms. To find the resistance of a 120 volt light bulb use the formula, Resistance in Ohms = Voltage (squared)/Watts. So for a 100 watt bulb at 120 volts the resistance is 120 volts x 120 volts = 14400/100 = 144 ohms. For a 60 watt bulb at 120 volts the resistance is 120 volts x 120 volts = 14400/60 = 240 ohms. As you can see this holds true to Ohm's law, current is inversely proportional to the resistance of the circuit. The higher the resistance of a load, the harder it is for the current to flow. In this case less current results in less light being emitted from the filament in the light bulb.
You cannot apply ohm's law to non-linear devices. This is because, the non-linearity introduces different V-I characteristics which cannot be answered by mere Ohm's law.
ohms law.
No, a higher wattage INCANDESCENT light bulb uses more current than a lower wattage INCANDESCENT light bulb. Some CF and LED bulbs are rated by the amount of light that an incandescent bulb would produce, but they are also rated by the wattage that they use.