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Why does a child on a toboggan fall back when the toboggan is given a sharp tug?
A child in a wagon seems to fall backward when you give the wagon a sharp pull forward because the force that is exerted on te wagon is greater than the force of the friction pushing the child forward while the wagon is accelerating forward. If the force was great enough or if the wagon were to continue being pushed with a constant or increasing force, the child would eventually fall off the wagon. If the wagon's surface had no friction and there was no wind blowing against the wagon but there was friction on the ground the wagon is rolling on, then the child would stay in the same position and would fall of the wagon if the wagon were to travel far enough. If the surface of the wagon had no friction, there was no other force stopping the wagon, then the child wouldn't move his position while the wagon wouldn't stop ever making it so the child had to eventually fall assuming the wagon is finite and doesn't go all the way around in a circle around a center of gravity.
What does friction have to do with pushing or pulling a wagon?
Friction is necessary to cause the wheels to rotate about the axis of the wagon-- without it the wagon would just slide over the surface.
If you push a crate at constant velocity how does friction acting on the crate compare with your pushing force?
If a wagon is moving at a constant velocity, the total applied force must equal the frictional forces that resist the continued motion of the wagon. If they were not equal, the wagon would accelerate. In positive acceleration, it would speed up, and in negative acceleration, it would slow down. Think it through and you'll see that this is the only answer that makes sense. And not only does it make sense, it is true. The laws of physics are in force here.
How much work is done by the girl pulling her brother who is in the wagon if she exerts a force of 50N at an angle of 30 degrees above the horizontal and travels 25m?
Work = (force) x (distance)Work = (33N) x (13m) = 429 N-m = 429 joulesIF the force is in exactly the same direction as the motion of the wagon.
One way to increase the force used to pull a wagon is to decrease the mass in the wagon true or false?
False. Since Force=mass*acceleration, decreasing mass will increase acceleration for the same applied force.
What are some examples of newtons law of motion?
Newtons second low of motion states that a force is equivalent to the product of mass and acceleration. A clear example is that it is easier to push something that is light than it is heavy. This is because it will accelerate faster with the same force applied.
What work have you done if you push a wagon with a force of 36 N for a distance of 2.0 m and the wagon continues to roll for 1.0 m after you stop pushing?
Distance * Force / Calories
Stepping from a wagon and watching the wagon move away from you is an example of what law?
Newton's Third Law of Motion.
Suppose you place a ball in the middle of a wagon and then accelerate the wagon forward describe the motion of the ball relative to the ground and the wagon?
This is an example of newton's first law, inertia, the ball was remaining still until an outside force moved it.
When you pull a wagon you are exerting a what on the wagon?
force
When you pull a wagon you are exerting what on the wagon?
force
Why does a child on a toboggan fall back when the toboggan is given a sharp tug?
A child in a wagon seems to fall backward when you give the wagon a sharp pull forward because the force that is exerted on te wagon is greater than the force of the friction pushing the child forward while the wagon is accelerating forward. If the force was great enough or if the wagon were to continue being pushed with a constant or increasing force, the child would eventually fall off the wagon. If the wagon's surface had no friction and there was no wind blowing against the wagon but there was friction on the ground the wagon is rolling on, then the child would stay in the same position and would fall of the wagon if the wagon were to travel far enough. If the surface of the wagon had no friction, there was no other force stopping the wagon, then the child wouldn't move his position while the wagon wouldn't stop ever making it so the child had to eventually fall assuming the wagon is finite and doesn't go all the way around in a circle around a center of gravity.
What does friction have to do with pushing or pulling a wagon?
Friction is necessary to cause the wheels to rotate about the axis of the wagon-- without it the wagon would just slide over the surface.
If you push a crate at constant velocity how does friction acting on the crate compare with your pushing force?
If a wagon is moving at a constant velocity, the total applied force must equal the frictional forces that resist the continued motion of the wagon. If they were not equal, the wagon would accelerate. In positive acceleration, it would speed up, and in negative acceleration, it would slow down. Think it through and you'll see that this is the only answer that makes sense. And not only does it make sense, it is true. The laws of physics are in force here.
How much work is done by the girl pulling her brother who is in the wagon if she exerts a force of 50N at an angle of 30 degrees above the horizontal and travels 25m?
Work = (force) x (distance)Work = (33N) x (13m) = 429 N-m = 429 joulesIF the force is in exactly the same direction as the motion of the wagon.
How do you reset circuit breaker in 1990 Camry wagon?
You reset a circuit breaker by pushing the reset button.
One way to increase the force used to pull a wagon is to decrease the mass in the wagon true or false?
False. Since Force=mass*acceleration, decreasing mass will increase acceleration for the same applied force.
