Yes it is. The BR took 4 bursts which is 12 bullets, while the DMR takes 5 pulls of the trigger or 5 bullets. (As long as the last burst for each gun is a headshot)
The DMR has been confirmed that it is coming back into the halo series. Aslo the br,ar, and the new rail gun is going to be in halo 4 as well.
yes it is since it more electronegative than Br
if the bond is more than .3 than it is considered polar. According to the electronegativity chart, "O" is 3.5, and "Br" is 2.8, a difference of .7. so... O-Br is polar.
Br-I
Br-I
Br for sure!
No. The Se ion will be larger than the Br ion. The more negative the anion's charge, the larger the radius (more electrons = stronger repulsion between the electrons; so, more distance between them). Se would become "Se2-" as an anion, and Br would become "Br1-". Because Se's "2-" anion charge is more negative than Br's "1-" anion charge, and because Se would have more relative electrons to protons than Br, there is more repulsion between electrons, and distance, within the Se ion. So, the Se ion has a larger radius. Hope it helps.
I can, but would I? Yes.<br><br>For example, in comparisons, you would say, "He is taller than I." "He is taller than me" is grammatically incorrect.<br><br>It would help, however, if you gave an example. You wouldn't say, "He gave it to I." <br><br><br>
Br
ch4 is the most volatile
if the bond is more than .3 than it is considered polar. According to the electronegativity chart, "O" is 3.5, and "Br" is 2.8, a difference of .7. so... O-Br is polar.
The C-N bond is more polar than the Br-S bond based on differences in electronegativity values (∆EN). The dipole will have the negative pole at the N and the positive pole at the C. For Br-S, the negative pole is the Br and the positive pole is the S.