Br for sure!
No, nitrogen does not have a low electron affinity. Electron affinity increases as you go up and to the right on the periodic table. Thus, Groups I and II elements (ex. Cs, Ba, Sr, etc.) have LOW electron affinities and the halogens in Group VII (Br, Cl, F, etc) have the HIGHEST electron affinities. Chlorine has the HIGHEST electron affinity on the periodic table.(Fluorine is an exception in this case.)
Br-, like the other halogens F-, Cl-, Br-, I-. They would obtain one electron to have noble gas electron configuration. Therefore, one negative charge.
Br- ion will have 8 valence electrons. So to write the Lewis structure, write the symbol Br, with 8 dots around it. Each dot will correspond to one electron.
The electron-dot structure for HBr would be:H:Br: (with two more pairs of dots on the top and bottom of Br)
The process of electron gain is called reduction. For example, if Br gains an electron, its oxidation number is reduced from 0 to -1, and will be written as Br-. The opposite of this (electron loss) would be called oxidation, or ionization.
Br-. Bromine will grab an electron to make itself more stable, which makes it a negative ion.
No, nitrogen does not have a low electron affinity. Electron affinity increases as you go up and to the right on the periodic table. Thus, Groups I and II elements (ex. Cs, Ba, Sr, etc.) have LOW electron affinities and the halogens in Group VII (Br, Cl, F, etc) have the HIGHEST electron affinities. Chlorine has the HIGHEST electron affinity on the periodic table.(Fluorine is an exception in this case.)
Br-, like the other halogens F-, Cl-, Br-, I-. They would obtain one electron to have noble gas electron configuration. Therefore, one negative charge.
Bromine (Br) forms a anion (negative charge) because it is a halogen, and it gains 1 electron. However, when it gains that electron (Br)- its name changes to Bromide ion.
the ions of Cl and Br both are negative 1. this means Cl and Br need one more electron to obtain a full shell. to complete their shells, Cl and Br form a covalent bond. also, Cl and Br are both nonmetals. 2 nonmetals cam only form a covalent bond.
Br- ion will have 8 valence electrons. So to write the Lewis structure, write the symbol Br, with 8 dots around it. Each dot will correspond to one electron.
Seesaw, as Br = 5 valence electrons, 1 electron for each F, one electron for the negative charge means it's a trigional byprimidal, however there is one unpaired set of electrons meaning it's a seesaw shape
The C-N bond is more polar than the Br-S bond based on differences in electronegativity values (∆EN). The dipole will have the negative pole at the N and the positive pole at the C. For Br-S, the negative pole is the Br and the positive pole is the S.
The electron-dot structure for HBr would be:H:Br: (with two more pairs of dots on the top and bottom of Br)
Br typically gains one electron to achieve a stable electron configuration, rather than losing electrons.
The process of electron gain is called reduction. For example, if Br gains an electron, its oxidation number is reduced from 0 to -1, and will be written as Br-. The opposite of this (electron loss) would be called oxidation, or ionization.
The ionic notation for Bromine is Br-. It gains one electron to form Br-