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Q: Is the equation 2NO2 - N2O4 an chemical equilibrium?
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Is 2NO2 ---- N2O4 a redox reaction?

no.


What happens to the reaction 2NO2 N2O4 57.2 kJ when the temperature of the reaction is increased?

This is an endothermic equilibrium reaction Thus, increase temperature will push the reaction to the right. So more N2O4 is produced


What is the name for the chemical formula N2O4?

It is Dinitrogen Tetroxide, also called Nitrogen peroxide. It is a dimer of Nitrogen dioxide, and exists in an equilibrium: NO2 ⇄ N2O4


What reactions would have a decrease in entropy?

2NO2(g) N2O4(g)


What is the chemical equation of nitrogen dioxide decomposes into oxygen gas and nitrogen gas?

The chemical formula for that reaction is 2n2o5 -->2 no2+3o2. It describes the process of two distinct compounds coming together to form two new ones.


Is N2O4 ---- 2NO2 a redox reaction?

No. The oxidation numbers of nitrogen and oxygen do not change.


What is the formula for dinitrogen tetraoxide?

The chemical formula for "Dinitrogen Tetroxide" is N204


What chemical is N2O4?

N2O4 is Dinitrogen tetroxide (nitrogen tetroxide or nitrogen peroxide).


What happens to the reaction 2 N O 2 in equilibrium with N 2 O 4 plus 57.3 kilojoules when the temperature of the reaction is increased?

This is an endothermic equilibrium reaction Thus, increase temperature will push the reaction to the right. So more N2O4 is produced


What is happening in the following equation N2O4 g arrow going right 2NO2 g?

One unit of dinitrogen tetraoxide gas is decomposing into two units of nitrogen dioxide gas.


What is the chemical name of N2O4?

Dinitrogen Tetroxide


Why the reaction mixture doesn't have 50 percents reactants and 50 percents products at equilibrium position?

Chemical equilibrium occurs when the rate of the forward reaction is equal to the rate of the reverse reaction. Take this example:2NO2(g) ↔N2O4(g)At this point of the reaction the rate of N2O4 produced from NO2 is the same as the rate of NO2 produced from N2O4. The key aspect to keep in mind is that the amounts (of moles) of products and reactants at equilibrium is not always 50%/50%. It is usually not.Finding the amounts of products and reactants present during a reaction can be found using Q. Q is known as the reaction quotient. Q can be found like so:Q=[products]/[reactants]reaction quotient =concentrations of products (M) / concentrations of reactantsQ is used to find this ratio at a certain point in time during a reaction (not atequlilibrium)Most likely, you will be given Keq, the equilibrium constant, for a reaction. The value tells you the concentrations of products/reactants at equilibrium. Comparing Q and Keqwill tell you whether a reaction is at equilibrium.Not to get off topic, the answer is that equilibrium does not mean that the reaction mixture has 50% reactants and 50% products. Equilibrium means that the rate of the forward reaction equals the rate of the reverse reaction.